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KonstantinChe [14]
2 years ago
8

Pleaseee I need help #22 and #23

Mathematics
1 answer:
mixas84 [53]2 years ago
7 0

Answer:

(8)

Step-by-step explanation:

(1+2)=

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The length of a rectangle is 5 yd less than three times the width, and the area of the rectangle is 28 yd2 . find the dimensions
Firdavs [7]
The answer is 4.

The formula for the area of a rectangle is A = lw. Substitute, so then it's 28 = (3x-5) * x, and you evaluate.

Hope this helps you! And rate so I can see if I did well!
8 0
3 years ago
Simplify radicals problems attached please help!
Finger [1]

Answer:

  G7.  (2√3)/3

  G8.  -2+√7

  G9.  (6 +2√2 -3√3 -√6)/7

Step-by-step explanation:

G7.

\dfrac{2}{\sqrt{3}}=\dfrac{2}{\sqrt{3}}\cdot\dfrac{\sqrt{3}}{\sqrt{3}}=\dfrac{2\sqrt{3}}{3}

__

G8.

\dfrac{3}{2 +\sqrt{7}}=\dfrac{3}{2+\sqrt{7}}\cdot\dfrac{2-\sqrt{7}}{2-\sqrt{7}}=\dfrac{6-3\sqrt{7}}{2^2-(\sqrt{7})^2}\\\\=\dfrac{6-3\sqrt{7}}{-3}=\sqrt{7}-2

__

G9.

\dfrac{2-\sqrt{3}}{3-\sqrt{2}}=\dfrac{2-\sqrt{3}}{3-\sqrt{2}}\cdot\dfrac{3+\sqrt{2}}{3+\sqrt{2}}=\dfrac{(2-\sqrt{3})(3+\sqrt{2})}{9-2}\\\\=\dfrac{6+2\sqrt{2}-3\sqrt{3}-\sqrt{6}}{7}

_____

<em>Comment on the problems</em>

In most cases, these expressions are the simplest possible (take the least amount of ink to draw, and take the fewest math operations to evaluate). What seems to be intended is that the denominator be made a rational number. This is done by multiplying the given fraction by a fraction equal to 1 that has the same denominator but with the sign of the radical reversed (unless, as in the first case, the radical is by itself).

The purpose of doing this is to take advantage of the fact that (a-b)(a+b) = a²-b², so if "a" or "b" is a square root, that root will not be seen in the product. In problem G9, we see this can make the numerator quite messy--not exactly a simpler form--but all the irrational numbers are in the numerator.

8 0
3 years ago
If the streets of a city are straight lines and the intersections are points, show how Principle 2 and Principle 3 might be illu
Naily [24]

Step-by-step explanation:

In the plane geometry Abeka, second edition, it is given :

Principle 2 states that between any two points, only one straight line can be drawn.

And according to principle 3 two straight lines interacts at one point only.

Thus this can be well illustrated by two straight lines which are represented by the streets of a city and these two streets intersects at a point.

6 0
3 years ago
What are the slopes for each one ?
sladkih [1.3K]

Answer:

the Slopes For each one are Positive

6 0
3 years ago
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Any hellllllllp please
katovenus [111]
The answer would be D how are the trails used
8 0
3 years ago
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