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artcher [175]
3 years ago
10

Which of the following are identities?

Mathematics
1 answer:
frosja888 [35]3 years ago
4 0

Answer:

A and D.

Step-by-step explanation:

(sin(x-y))/(cosxcosy)

(sinxcosy - cosxsiny) / cosxcosy

=  sinx / cosx - siny/cosy

= tanx - tany.  

So A is an identity.

B.   (sin(x+y))/(sinxsiny)

= sinx cosy + cosx siny / sinxsiny

= cosy/siny + cosx/sinx

= 1/tany + 1/tanx which is not identical with 1-tanxtany.

C.  tan ( x - pi/4) =    ( tan x - 1) / (1 + tanx) : - not identical to tanx - 1.

D.  cos( x + (pi/6) = cosxcos(pi/6) - sinxsin(pi/6)

     =    0.866cosx - 0.5sinx

    - sin(x - (pi/3) = -(sinxcos(pi/3) - cosxsin(p/3))

     =   - (0.5sinx - 0.866cosx0

     = 0.866cos x - 0.5sinx.

which are identical.

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Step-by-step explanation:

put x = -6 in the equation.

= -6 ( -6). + 7 =. 36 + 7 = 43

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3 years ago
Factor x2 − 8x + 9.
kolezko [41]

x^2 − 8x + 9

What two numbers when multiplied yield 9 but when added yield -8?

There are no such numbers.

Use the quadratic formula.

7 0
3 years ago
Urgent, Please help!
yarga [219]

Answer:

<h2>min: 52</h2><h2>max: 78</h2><h2>median: 63</h2><h2>lower quartile median: 54</h2><h2>upper quartile median: 73</h2><h2>interquartile range: 19</h2>

Step-by-step explanation:

the temperatures ordered from least to greatest

52, 53, 54, 54, 57, 62, 64, 69, 73, 73, 77, 78

the min is 52

the max is 78

median:

52, 53, 54, 54, 57, 62, 64, 69, 73, 73, 77, 78

(62+64)/2=126/2=63

thus the median is 63

now we don't include the median in finding the upper and lower quartile medians:

lower quartile median:

52, 53, 54, 54, 57, 62

54 (same #s no need to add up and divide by 2)

upper quartile median:

64, 69, 73, 73, 77, 78

73 (same #s no need to add up and divide by 2)

interquartile range is:

upper quartile median-lower quartile median:

73-54

19

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Answer:

b

Step-by-step explanation:

because the 1 is negative

8 0
3 years ago
Read 2 more answers
What is the expression: the quantity n minus 6 cubed? (in algebraic expression)
nevsk [136]

Answer:

The equation is either n-6^3 (this is without cubing the 6, this is probably what your teacher is looking for.) or n-216 (this is what the equation looks like when 6 is cubed)

8 0
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