Answer:
75 days
Step-by-step explanation:
The multiplier each day is ...
(1/2)^(t/15)
Then we want to find t such that ...
5 = 160·(1/2)^(t/15) . . . . . . 5 mg are left after t days
5/160 = (1/2)^(t/15) . . . . . . divide by 160
1/32 = (1/2)^5 = (1/2)^(t/15) . . . . rewrite the left side
Equating exponents (equivalent to taking logs), we get ...
5 = t/15
5·15 = 75 = t . . . . . multiply by 15 to find t
After 75 days, there will be 5 mg left.
Answer:
60.9º
Step-by-step explanation:
tan = opp/adj
tanX = 45/25
X = arctan 45/25
use calculator
X = 60.945395900922855
Rounded
60.9º
One solution. One. Ask me if you have any questions
A complete load of concrete = 8 parts gravel + 7 parts water + 5 parts cement.
Total number of parts in every load = 8 + 7 + 5 = 20 parts
If total load = 220 kg, then 20 parts = 220 kg
Divide each side by 20 : 1 part = 11 kg
gravel = 8 parts = 8 x 11 kg = <em>88 kg</em>
water = 7 parts = 7 x 11 kg = <em>77 kg</em>
cement = 5 parts = 5 x 11 kg = <em>55 kg</em>
<u>Check:</u> 88 + 77 + 55 = 220 yay !
The measures of the angles in a triangle add up to 180°.
The measures of the angles are 43°, 47° and 90°.
