When you have something like this, all you need to do is substitute the values, the last is for what value of x
For the first one;
((x^2+1)+(x-2))(2)
(x^2+x-1)(2)
(2)^2+(2)-1
4+2-1
5
For the second one;
((x^2+1)-(x-2))(3)
(x^2-x+3)(3)
(3)^2-(3)+3
9-3+3
9
For the last one;
3(x^2+1)(7)+2(x-2)(3)
3((7)^2+7)+2((3)-2)
3(49+7)+2(3-2)
3(56)+2(1)
168+2
170
2/3y = 18
y = 18 / (2/3)
y = 18 * 3/2
y = 54/2
y = 27 <==
Answer:
Greater than or equal to, or D.
80 goes into 142 once, so one is our whole number. there are still 62 / 80 left, so we reduce this fraction. The answer is
1
Answer:
The value of the given expression is 27.1
Step-by-step explanation:
We are given an expression of two variable x and y.
We need to find the value of expression at x = 3 and y = 4
So first put x = 3 and y = 4 into expression and simplify
1/2 x 3 (3) + 3.4 x 4
➡️ 1/2 x 27 + 13.6
➡️ 27/2 + 13.6
➡️ 13.5 + 13.6
Now, add both of the numbers together. ( as an addition problem)
Therefore, when you ad the 2 together, you get the total of 27.1
