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1 year ago

Find the determinant of this matrix:

Mathematics

2 answers:

Margarita [4]1 year ago

6 0

Answer:

-1

Step-by-step explanation:

Formula to the determinant is:

$\left[\begin{array}{ccc}a&b\\c&d\end{array}\right] = ad-bc$

0(0)–1(1)

0-1

-1

Dmitrij [34]1 year ago

6 0

Answer:

-1

Step-by-step explanation:

Formula: ad-bc

0(0) - 1(1)

0-1

-1

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2)

a)

$\bf a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}\\\\
-------------------------------\\\\
(4x^5\cdot x^{\frac{1}{3}})+(2x^4\cdot x^{\frac{1}{3}})-(7x^3\cdot x^{\frac{1}{3}})+(3x^2\cdot x^{\frac{1}{3}})\\\\+(9x^1\cdot x^{\frac{1}{3}})-(1\cdot x^{\frac{1}{3}})
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b)

$\bf \cfrac{4x^5+2x^4-7x^3+3x^2+9x-1}{x^{\frac{1}{3}}}\impliedby \textit{distributing the denominator}
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3)

$\bf \begin{cases}
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g(x)=5x^2-2x+\sqrt[5]{x}\implies &g(x)=5x^2-2x+x^{\frac{1}{5}}
\end{cases}
\\\\\\
\textit{let's multiply the terms from f(x) by each term in g(x)}
\\\\\\
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\\\\\\
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