Question

Which equations have a leading coefficient of 3 and a constant term of –2? check all that apply. 0 = 3x2 2x – 2 0 = –2 – 3x2 3 0 = –3x 3x2 – 2 0 = 3x2 x 2 0 = –1x – 2 3x2

Answer 1

The equations which have a leading coefficient of 3 and a constant term of –2 are 0 = 3x² +2x - 2 and 0=3x²-1x-2.

What is a quadratic equation?

A quadratic equation is the equation in which the unknown variable is one and the highest power of the unknown variable is two.

The standard form of the quadratic equation is,

$ax^2+bx+c=0$

Here,(a,b, c) is the real numbers and (x) is the variable.In this equation, a is the coefficient of the highest term and c is the constant term.

The equations which has the leading coefficient of 3 and a constant term of –2 has to be find out.

The first equation given in the problem is,

$0 = 3x^2 +2x - 2$

In this equation, the coefficient of the term which has the highest power is 3 and the constant term is -2. Thus, this option is correct.

The second equation given in the problem is,

$0 = -2 - 3x^2 +3$

Rearrange the equation as,

$0 = -2 - 3x^2 +3\\0=-3x^2+1$

In this equation, the coefficient of the term which has the highest power is -3 and the constant term is 1. Thus, this option is not correct.

The third equation given in the problem is,

$0 = 3x^2 +x +2$

In this equation, the coefficient of the term which has the highest power is 3 and the constant term is 2. Thus, this option is not correct.

The fourth equation given in the problem is,

$0 = -1x - 2 +3x^2$

Rearrange the equation as,

$0=3x^2-1x-2$

In this equation, the coefficient of the term which has the highest power is 3 and the continuant term is -2. Thus, this option is correct.

Hence, the equations which have a leading coefficient of 3 and a constant term of –2 are 0 = 3x² +2x - 2 and 0=3x²-1x-2.

Learn more about the quadratic equation here;

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