Please help with math please.
1 answer:
Subtract the constant vector that is on the left. The arithmetic applies to corresponding elements of the vectors.
![A=\left[\begin{array}{cccc}0&1&-2&3\end{array}\right] -\left[\begin{array}{cccc}11&17&-8&13\end{array}\right]\\\\A=\left[\begin{array}{cccc}-11&-16&6&-10\end{array}\right]\\\\a_{11}=-11\\a_{12}=-16\\a_{13}=6\\a_{14}=-10](https://tex.z-dn.net/?f=%20A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D0%261%26-2%263%5Cend%7Barray%7D%5Cright%5D%20-%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D11%2617%26-8%2613%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5CA%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D-11%26-16%266%26-10%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5Ca_%7B11%7D%3D-11%5C%5Ca_%7B12%7D%3D-16%5C%5Ca_%7B13%7D%3D6%5C%5Ca_%7B14%7D%3D-10%20)
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Step-by-step explanation:
![\bigg( \frac{3 {a}^{ - 2} {b}^{6} }{2 {a}^{ - 1} {b}^{5} } \bigg)^{2} \\ \\ = \bigg( \frac{3 {b}^{6 - 5} }{2 {a}^{ 2- 1} } \bigg)^{2} \\ \\ = \bigg( \frac{3 {b}^{1} }{2 {a}^{ 1} } \bigg)^{2} \\ \\ = \bigg( \frac{3 {b}}{2 {a}} \bigg)^{2} \\ \\ = \bigg( \frac{3 \times ( - 2)}{2 \times 3} \bigg)^{2} \\ \\ = \bigg( \frac{ - 6}{6} \bigg)^{2} \\ \\ = ( - 1)^{2} \\ \\ \huge\red {\boxed {\therefore \: \bigg( \frac{3 {a}^{ - 2} {b}^{6} }{2 {a}^{ - 1} {b}^{5} } \bigg)^{2} = 1}} \\](https://tex.z-dn.net/?f=%20%5Cbigg%28%20%20%5Cfrac%7B3%20%7Ba%7D%5E%7B%20-%202%7D%20%20%7Bb%7D%5E%7B6%7D%20%7D%7B2%20%7Ba%7D%5E%7B%20-%201%7D%20%20%7Bb%7D%5E%7B5%7D%20%7D%20%5Cbigg%29%5E%7B2%7D%20%20%5C%5C%20%20%5C%5C%20%20%3D%20%20%5Cbigg%28%20%20%5Cfrac%7B3%20%20%7Bb%7D%5E%7B6%20-%205%7D%20%7D%7B2%20%7Ba%7D%5E%7B%202-%201%7D%20%7D%20%5Cbigg%29%5E%7B2%7D%20%20%20%5C%5C%20%20%5C%5C%20%20%3D%20%20%5Cbigg%28%20%20%5Cfrac%7B3%20%20%7Bb%7D%5E%7B1%7D%20%7D%7B2%20%7Ba%7D%5E%7B%20%201%7D%20%7D%20%5Cbigg%29%5E%7B2%7D%20%20%20%5C%5C%20%20%5C%5C%20%20%3D%20%20%5Cbigg%28%20%20%5Cfrac%7B3%20%20%7Bb%7D%7D%7B2%20%7Ba%7D%7D%20%5Cbigg%29%5E%7B2%7D%20%20%20%5C%5C%20%20%5C%5C%20%20%20%3D%20%20%5Cbigg%28%20%20%5Cfrac%7B3%20%20%20%5Ctimes%20%28%20-%202%29%7D%7B2%20%20%5Ctimes%203%7D%20%5Cbigg%29%5E%7B2%7D%20%20%5C%5C%20%20%5C%5C%20%20%3D%20%5Cbigg%28%20%20%5Cfrac%7B%20-%206%7D%7B6%7D%20%5Cbigg%29%5E%7B2%7D%20%20%5C%5C%20%20%5C%5C%20%20%3D%20%28%20-%201%29%5E%7B2%7D%20%20%5C%5C%20%20%5C%5C%20%5Chuge%5Cred%20%7B%5Cboxed%20%7B%5Ctherefore%20%5C%3A%20%20%20%20%5Cbigg%28%20%20%5Cfrac%7B3%20%7Ba%7D%5E%7B%20-%202%7D%20%20%7Bb%7D%5E%7B6%7D%20%7D%7B2%20%7Ba%7D%5E%7B%20-%201%7D%20%20%7Bb%7D%5E%7B5%7D%20%7D%20%5Cbigg%29%5E%7B2%7D%20%20%3D%201%7D%7D%20%5C%5C%20)
Find A ∩ B if A = {4, 7, 10, 13, 17} and B = {3, 5, 7, 9}. A. {3, 4, 5, 7, 9, 10, 13, 17} B. Ø C. {7}
vladimir1956 [14]
Answer:
C. {7}
Step-by-step explanation:
Given,
A = {4, 7, 10, 13, 17}
B = {3, 5, 7, 9}
To find : A ∩ B
A ∩ B means common in both sets of A and B
So,
A ∩ B = {7)
Subtract 8 from each side:
-4x = 40
Divide each side by -4 :
x = -10
Problem 1
A = length times width
A = w(w + 0.6)
A = w^2 + 0.6w
Answer choice D.
Problem 2
16/9 = 42/x
9(42) = 16x
378 = 16x
378/16 = x
23.625 = x
Answer choice C.
Problem 3
f(-5) = 4(-5) + 3
f(-5) = -20 + 3
f(-5) = -17
Answer choice B.
Bruce has a 1/12 chance of winning.