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zvonat [6]
2 years ago
11

Is this relation a function? Justify your answer. CH w . HAN . 5 7 8 10 12 A. Yes, because the number of x-values is the same as

the number of y values B. Yes, because every x- and y-value is positive. C. No, because two points with the same x-value have different ; values. D. No, because two points with the same y-value have different x- values​
Mathematics
1 answer:
Stolb23 [73]2 years ago
5 0

Answergood question

Step-by-step explanation:

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What is the the greatest common factor of 10m" and 4m”.
Ilya [14]

Answer:

2

Step-by-step explanation:

4 dvided by 2 is 2

10 didide by 2 is 5

4 0
3 years ago
The body of a 154 pound person contains approximately 4 × 10-1 milligrams of gold and 16 × 101 milligrams of aluminum. Based on
Eddi Din [679]

The number of milligrams of aluminum is 400 times the number of milligrams of gold in the body.

<u><em>Explanation</em></u>

Lets assume, the number of milligrams of aluminum is x times the number of milligrams of gold in the body.

The body of a 154 pound person contains approximately 4 × 10⁻¹ milligrams of gold and 16 × 10¹ milligrams of aluminum.

So the equation will be...

(4*10^-^1)*x= 16*10^1\\ \\ x= \frac{16*10^1}{4*10^-^1}= 4*10^2=400

So, the number of milligrams of aluminum is 400 times the number of milligrams of gold in the body.

3 0
4 years ago
A student ticket to the movie cost $4
Shalnov [3]

Answer:(X x 4)=

Step-by-step explanation:

Basically u times how many tickets u need times how much it cost

Example( 1ticket X 4dollars) =4 dollars

8 0
3 years ago
Read 2 more answers
EXPENSES: Camille has no more than $50.00 to spend each week for lunch and bus fare. Lunch costs $3.00 each day, and bus fare is
Afina-wow [57]

Answer:

Inequality: 3.00 L + 1.75B \leq 50

She can afford to buy the lunch and bus rides

Step-by-step explanation:

Given

Maximum\ Amount = \$50.00

Lunch = \$3.00 daily

Bus\ Fare = \$1.75 daily

Solving (a) The inequality

Let bus ride be represented with B and Lunch be represented with L

If 1 bus ride costs $1.75, then

B bus ride would cost $1.75 * B

If 1 lunch costs $3.00, then

L lunch would cost $3.00 * L

Total Spending is then the sum of the above expression i.e.

$3.00 * L + $1.75 * B

The question says Camille can not spend more than $50.00.

This is represented by less than or equal to.

So, the expression is:

3.00 * L + 1.75 * B \leq 50

3.00 L + 1.75B \leq 50

Solving (b): Can she afford 7 lunch and 14 bus ride?

To do this, we simply substitute 7 for L and 14 for B

3.00 * 7 + 1.75 * 14 \leq 50

21 + 24.5 \leq 50

45.5 \leq 50

The above inequality is true.

<em>Hence, she can afford to buy the lunch and bus rides</em>

8 0
3 years ago
You deposit $70 in a savings account that pays an annual interest rate of 30%. How much simple interest would you earn in 2.5 ye
blagie [28]
The formula is
I=prt
I interest earned?
P principle 70
R interest rate 0.3
T time 2.5 years
I=70×0.3×2.5
I=52.5
4 0
4 years ago
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