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Dovator [93]
3 years ago
9

The body of a 154 pound person contains approximately 4 × 10-1 milligrams of gold and 16 × 101 milligrams of aluminum. Based on

this information, the number of milligrams of aluminum in the body is how many times the number of milligrams of gold in the body?
Mathematics
1 answer:
Eddi Din [679]3 years ago
3 0

The number of milligrams of aluminum is 400 times the number of milligrams of gold in the body.

<u><em>Explanation</em></u>

Lets assume, the number of milligrams of aluminum is x times the number of milligrams of gold in the body.

The body of a 154 pound person contains approximately 4 × 10⁻¹ milligrams of gold and 16 × 10¹ milligrams of aluminum.

So the equation will be...

(4*10^-^1)*x= 16*10^1\\ \\ x= \frac{16*10^1}{4*10^-^1}= 4*10^2=400

So, the number of milligrams of aluminum is 400 times the number of milligrams of gold in the body.

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During a concert, $3280 was received. A total of 760 people attended. Reserved seats were $6 and general admission seats were $4
Andre45 [30]

Answer:

The number of reserved seat is 120 and number of general seat is 640.

Step-by-step explanation:

Given,

Total number of seats = 760

Total collected Money = $3280

Solution,

Let the total number of reserved seat be x.

And  the total number of general seat be y

Hence total number of seats is the sum of total number of reserved seat and  the total number of general seats.

So the equation can be written as;

x+y=760\ \ \ \ equation\ 1

Again, total money collected is the sum of fees of one reserved seat times total number of reserved seat and fees of one general seat times the total number of general seats.

So the equation can be written as;

6x+4y=3280\ \ \ \ \ equation\ 2

Now, multiplying equation 1 by 4 and then subtract it from equation 2.

4x+4y=3040

(6x+4y)-(4x+4y)=3280-3040\\\\2x=240\\\\x=\frac{240}{2}=120

On substituting the value of x in equation 1, we get;

x+y=760\\120+y=760\\y=760-120=640

Thus the number of reserved seat is 120 and number of general seat is 640.

8 0
3 years ago
What is the greatest common factor of 20, 50, and 25
steposvetlana [31]

Answer:

Step-by-step explanation:

5 0
3 years ago
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1.find the sum. (3^3+5x^2+3x-7)+(8x-6x^2+6)<br> 2. Find the Difference: (8x-4x^2+3\)-(x^3+7x^2+3x-8)
vlada-n [284]

1.

(3^3+5x^2+3x-7)+(8x-6x^2+6)=\\\\=27\ \underline{+\,5x^2}\ \underline{ \underline{+\,3x}}-7\ \underline{\underline{\,+8x}}\ \underline{-\,6x^2}+6=\\\\=-x^2+11x+26

or if you mean (3x^3+5x^2+3x-7)+(8x-6x^2+6):

(3x^3+5x^2+3x-7)+(8x-6x^2+6)=\\\\=3x^3\ \underline{+\,5x^2}\ \underline{ \underline{+\,3x}}-7\ \underline{\underline{\,+8x}}\ \underline{-\,6x^2}+6=\\\\=3x^3-x^2+11x-1

2.

(8x-4x^2+3)-(x^3+7x^2+3x-8)=\\\\=\underline{8x}\ \underline{\underline{-\ 4x^2}}+3-x^3\ \underline{\underline{-\,7x^2}}\ \underline{-\,3x}+8=\\\\=-x^3-11x^2+5x+10

3 0
3 years ago
Solve for x. 5x^2 – 45 = 0
mamaluj [8]

5x^2-45=0

<em>*Add 45 to both sides*</em>

5x^2=45

<em>*Divide both sides by 5*</em>

x^2=9

<em>*Take the square root of both sides*</em>

x=+/-9

Hope this helps!!

3 0
3 years ago
Read 2 more answers
What is the length of EF in the right triangle below?
Goshia [24]

Answer:

Its SQUARE ROOT 217

\sqrt{217}

AP3X HOPE THIS HELPS

6 0
2 years ago
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