The body of a 154 pound person contains approximately 4 × 10-1 milligrams of gold and 16 × 101 milligrams of aluminum. Based on
1 answer:
The number of milligrams of aluminum is 400 times the number of milligrams of gold in the body.
<u><em>Explanation</em></u>
Lets assume, the number of milligrams of aluminum is times the number of milligrams of gold in the body.
The body of a 154 pound person contains approximately 4 × 10⁻¹ milligrams of gold and 16 × 10¹ milligrams of aluminum.
So the equation will be...
So, the number of milligrams of aluminum is 400 times the number of milligrams of gold in the body.
You might be interested in
Answer:
a) -1.25
b) 0.2112
c) -1.96
Step-by-step explanation:
Data provided in the question:
Sample size, n = 400
H0 : p = 20
= 175
Now,
a) The test statistic is given as:
Z =
on substituting the respective values, we get
Z =
= -1.25
b) The p-value = 2 × P(Z <-1.25)
Now from the standard normal table
P(Z <-1.25) = 10.56% = 0.1056
Thus,
p-value = 2 × 1056 = 0.2112
c) for a = 0.05,
the critical value is i.e
Now from standard normal table
= -1.96