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2 years ago

Which best describes the range of the function f(x) = Two-thirds(6)x after it has been reflected over the x-axis?

Mathematics

1 answer:

algol132 years ago

4 1

Answer:

Range: ( − ∞ , ∞ ) , { y | y ∈ R }

Step-by-step explanation:

Slope: 4

y-intercept: (0,0)

X Y

0 0

1 4

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A pancake recpe calls for 1/2 cup of milk and 3/4 Of a cup of flour.If you multiply the recipe by 5 how much flour will you need

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3 years ago

Solve. k + 6 > 19

Readme [11.4K]

Answer:

k > 13

Step-by-step explanation:

$k+6 > 19\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:k > 13\:\\ \:\mathrm{Interval\:Notation:}&\:\left(13,\:\infty \:\right)\end{bmatrix}$

$\mathrm{Subtract\:}6\mathrm{\:from\:both\:sides}$

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$\mathrm{Simplify}$

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2 years ago

In a group of 60 students, 12 students take algebra 1, 18 students take algebra 2, and 8 students take both subjects. How many s

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3 years ago

Read 2 more answers

2. Draw the image of RST under the dilation with scale factor 2/3 and center of dilation (1,-1). Label the image RST .

professor190 [17]

Answer:

From the graph: we have the coordinates of RST i.e,

R = (2,1) , S = (2,-2) , T = (-1,-2)

Also, it is given the scale factor $\frac{2}{3}$ and center of dilation C (1,-1)

The mapping rule for the center of dilation applied for the triangle as shown below:

$(x, y) \rightarrow (\frac{2}{3}(x-1)+1, \frac{2}{3}(y+1)-1)$

$(x, y) \rightarrow (\frac{2}{3}x -\frac{2}{3}+1 , \frac{2}{3}y+\frac{2}{3}-1)$

$(x, y) \rightarrow (\frac{2}{3}x+\frac{1}{3} , \frac{2}{3}y-\frac{1}{3} )$

Now,

for R = (2,1)

the image R' = $(\frac{2}{3}(2)+\frac{1}{3} , \frac{2}{3}(1)-\frac{1}{3} )$ or

$(\frac{4}{3}+\frac{1}{3} , \frac{2}{3}-\frac{1}{3} )$

⇒ R' = $(\frac{5}{3} , \frac{1}{3})$

For S = (2, -2) ,

the image S'= $(\frac{2}{3}(2)+\frac{1}{3} , \frac{2}{3}(-2)-\frac{1}{3} )$ or

$(\frac{4}{3}+\frac{1}{3} , \frac{-4}{3}-\frac{1}{3} )$

⇒ S' = $(\frac{5}{3} , -\frac{5}{3})$

and For T = (-1, -2)

The image T' = $(\frac{2}{3}(-1)+\frac{1}{3} , \frac{2}{3}(-2)-\frac{1}{3} )$ or

$(\frac{-2}{3}+\frac{1}{3} , \frac{-4}{3}-\frac{1}{3} )$

⇒ T' = $(\frac{-1}{3} , \frac{-5}{3})$

Now, label the image of RST on the graph as shown below in the attachment:

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