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2 years ago

The ratio of the surface areas of two spheres is 1:9.

Mathematics

1 answer:

lapo4ka [179]2 years ago

7 0

Answer:

Step-by-step explanation:

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Please help!! QUESTION IS BELOW

Andrew [12]

Answer:

Step-by-step explanation:

√((5-1)²+ (4 - (-6))²

√(4)² + (10)²

√(16+100)

√116

2√(29)

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1 year ago

)Tessa had $35. She bought a book for $7 and a magazine for $5. Which expression correctly shows the total money Tessa has left?

Sergeu [11.5K]

Total - book $ - magazine $

Which is equal to:

Total + (-book $) + (-magazine $)
$35 + (-$7) + (-$5)

ANSWER: (C) $35 + (-$7) + (-$5)

Hope this helps! :)

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3 years ago

Talk to me plz im am rlly lonely :/

Marina86 [1]

Hi, How are you? i hope your well <3

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2 years ago

Read 2 more answers

PLZ HELP ASAP The table records the rainfall in two cities during a particular week. Which statements about the data are true?

timofeeve [1]

To answer this question you will find the means and the mean absolute deviations and compare them.

The correct answers are
A and C.

Please see the attached picture for the organized work.

6 0

3 years ago

Read 2 more answers

Solve the following system of linear equations: 3x1+6x2+6x3 = -9 -2x1–3x2-3x3 = 3 If the system has infinitely many solutions, y

choli [55]

Answer:

The set of solutions is $\{\left[\begin{array}{c}x\\y\\z\end{array}\right]=\left[\begin{array}{c}12\\-7-r\\r\end{array}\right]: \text{r is a real number} \}$

Step-by-step explanation:

The augmented matrix of the system is $\left[\begin{array}{ccccc}3&6&6&-9\\-2&-3&-3&3\end{array}\right]$ .

We will use rows operations for find the echelon form of the matrix.

In row 2 we subtract $\frac{2}{3}$ from row 1. (R2- 2/3R1) and we obtain the matrix $\left[\begin{array}{cccc}3&6&6&-9\\0&1&1&-7\end{array}\right]$
We multiply the row 1 by $\frac{1}{3}$ .

Now we solve for the unknown variables:

$x_2+x_3=-7$ , $x_2=-7-x_3$
$x_1+2x_2+2x_3=-2$ , $x_1+2(-7-x_3)+2x_3=-2$ then $x_1=12$

The system has a free variable, the the system has infinite solutions and the set of solutions is $\{\left[\begin{array}{c}x\\y\\z\end{array}\right]=\left[\begin{array}{c}12\\-7-r\\r\end{array}\right]: \text{r is a real number} \}$

6 0

3 years ago