To solve this, you have to know that the first derivative of a function is its slope. When an interval is increasing, it has a positive slope. Thus, we are trying to solve for when the first derivative of a function is positive/negative.
f(x)=2x^3+6x^2-18x+2
f'(x)=6x^2+12x-18
f'(x)=6(x^2+2x-3)
f'(x)=6(x+3)(x-1)
So the zeroes of f'(x) are at x=1, x=-3
Because there is no multiplicity, when the function passes a zero, he y value is changing signs.
Since f'(0)=-18, intervals -3<x<1 is decreasing(because -3<0<1)
Thus, every other portion of the graph is increasing.
Therefore, you get:
Increasing: (negative infinite, -3), (1, infinite)
Decreasing:(-3,1)
Answer:
Step-by-step explanation:
X=(6,-2)
Y=(0,5)
m
9 + h = 55/5
9 + h = 11
11 - 9 = h
2 = h
The opposite of addition is subtraction, Subtract 9 from both sides, The opposite of multiplication is division, divide both sides by 5 is the first step, and final answer is h = 2.
Answer:
Lowest score needed=4.92
Step-by-step explanation:
Using the standard normal distribution table we find the value of standard normal deviate corresponding to area of 15%
For area of 15% we have Z= -1.04
Thus we have
Applying values we get
Thus lowest score needed = 4.92
Answer:
(x,y) = (-3,-2)
Step-by-step explanation: Please brainliest!
