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3 years ago

I WILL GIVE BRAINLIEST! :3PLEASE HELP!

Mathematics

1 answer:

algol [13]3 years ago

3 0

Answer:

9×(t+5)= 9t+45

Step-by-step explanation:

The distributive property states that

x(y+z)=xy+xz

here 9×(t+5) = 9(t+5)=9t+9(5)= 9t+45.

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A cylinder and a sphere have the same radius and volume. The height of the cylinder is 12 cm. What is the volume of the sphere r

Sedaia [141]

Answer:

3054

Step-by-step explanation:

The formula for cylinder volume is

V1 = π * r^2 *h

while formula for sphere volume is

V2= 4/3 * π * r^3

Since the height of the cylinder is 12, we can substitute h the equation into

V1 = π * r^2 *12

The volume and radius of the cylinder are the same as the sphere, so we can combine both equations to find r.

V1= V2

π * r^2 *12 = 4/3 * π * r^3

12 = 4/3 * r

r= 12*3/4

r=9

After we find the radius, we can find the sphere volume

V2= 4/3 * π * r^3

V2= 4/3 * π * 9^3

V2= 3053.62 = 3054

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3 years ago

I need to figure out which ones are irrational. please help

julsineya [31]

Fatmagul neushe mode

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2 years ago

A cylindrical roller 2.5 m in length, 1.5 m in radius when rolled on a road was found to cover the area of 16500 m2 . How many r

eduard

Answer:

701 revolutions

Step-by-step explanation:

Given: Length= 2.5 m

Radius= 1.5 m

Area covered by roller= 16500 m²

Now, finding the Lateral surface area of cylinder to know area covered by roller in one revolution of cylindrical roller.

Remember; Lateral surface area of an object is the measurement of the area of all sides excluding area of base and its top.

Formula; Lateral surface area of cylinder= $2\pi rh$

Considering, π= 3.14

⇒ lateral surface area of cylinder= $2\times 3.14\times 1.5\times 2.5$

⇒ lateral surface area of cylinder= $23.55 \ m^{2}$

∴ Area covered by cylindrical roller in one revolution is 23.55 m²

Next finding total number of revolution to cover 16500 m² area.

Total number of revolution= $\frac{16500}{23.55} = 700.6369 \approx 701$

Hence, Cyindrical roller make 701 revolution to cover 16500 m² area.

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