Hi im maddie im only in 5th grade tgo but it says to express nine thousandsths as a decimal

Mathematics

2 answers:

monitta3 years ago

8 0

Answer:

0.009

Step-by-step explanation:

Simply move the decimal point from nine- then move it to the right three times.

If you need any more help, do not hesitate to ask me. :)

melomori [17]3 years ago

8 0

Answer: 0.009 hope this helps.

You might be interested in

Tuesday and Wednesday work

AURORKA [14]

Prime factorizations - Wednesday work
1. 44 2^2 • 11
2. 125 5^3
3. 85 5 • 17
4. 39 3 • 13
5. 63 3^2 • 7
6. 240 2^4 • 3 • 5
7. 87 3 • 29
8. 45 3^2 • 5

8 0

3 years ago

Given that f(x) = 19x2 + 152, solve the equation f(x) = 0

telo118 [61]

Option A

The solution is:

$x = \pm 2i \sqrt{2}$

Solution:

$f(x) = 19x^2+152$

We have to solve the equation f(x) = 0

Let f(x) = 0

$0=19x^2+152$

Solve the above equation

$19x^2 + 152 = 0$

$\mathrm{Subtract\:}152\mathrm{\:from\:both\:sides}\\\\19x^2+152-152=0-152\\\\Simplify\ the\ above\ equation\\\\19x^2 = -152\\\\\mathrm{Divide\:both\:sides\:by\:}19\\\\\frac{19x^2}{19} = \frac{-152}{19}\\\\x^2 = -8$

Take square root on both sides

$x = \pm \sqrt{-8}\\\\x = \pm \sqrt{-1}\sqrt{8}\\\\\mathrm{Apply\:imaginary\:number\:rule}:\quad \sqrt{-1}=i\\\\x = \pm i\sqrt{8}\\\\x = \pm i \sqrt{2 \times 2 \times 2}\\\\x = \pm 2i\sqrt{2}$