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Veseljchak [2.6K]
3 years ago
8

Please help me!

Mathematics
1 answer:
Triss [41]3 years ago
8 0

\bf \textit{area of a sector of a circle}\\\\ A=\cfrac{\theta r^2}{2}~~ \begin{cases} r=radius\\ \theta =angle~in\\ \qquad radians\\ ------\\ r=5\\ \theta =\frac{\pi }{4} \end{cases}\implies A=\cfrac{\frac{\pi }{4}\cdot 5^2}{2}\implies A=\cfrac{\quad \frac{25\pi }{4}\quad }{\frac{2}{1}} \\\\\\ A=\cfrac{25\pi }{4}\cdot \cfrac{1}{2}\implies A=\cfrac{25\pi }{8}

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This is algebra 2. Would like an answer ASAP. Thanks! Between the two chunks of numbers, thats a division sign, not an addition
NeX [460]

Answer:

Simplified form of \frac{x+1}{x^2+x-6}\div \frac{x^2+5x+4}{x-2} is \mathbf{\frac{1}{(x+3)(x+4)} }

Option A is correct answer.

Step-by-step explanation:

We need to find simplified form of \frac{x+1}{x^2+x-6}\div \frac{x^2+5x+4}{x-2}

Solving the given expression:

\frac{x+1}{x^2+x-6}\div \frac{x^2+5x+4}{x-2}

First we find factors of x^2+x-6

x^2+x-6 \\= x^2+3x-2x-6\\= x(x+3)-2(x+3)\\=(x-2)(x+3)

So, factors of x^2+x-6 are (x-2)(x+3)

Now, fining the factors of x^2+5x+4

x^2+5x+4\\=x^2+4x+x+4\\=x(x+4)+1(x+4)\\=(x+1)(x+4)

So, factors of x^2+5x+4 are (x+1)(x+4)\\

Now the given expression will become:

\frac{x+1}{(x-2)(x+3)}\div \frac{(x+1)(x+4)}{x-2}

Now, converting division sign into multiplication sign:

=\frac{x+1}{(x-2)(x+3)}\times \frac{x-2} {(x+1)(x+4)}\\Cancelling, \:common\:terms\\=\frac{1}{(x+3)(x+4)}

So, simplified form of \frac{x+1}{x^2+x-6}\div \frac{x^2+5x+4}{x-2} is \mathbf{\frac{1}{(x+3)(x+4)} }

Option A is correct answer.

4 0
3 years ago
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Tan(35)=ck/cd
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Tan(65)=cj/cd
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3 years ago
Get money to answer this.
IRINA_888 [86]

Answer:

64

Step-by-step explanation:

i think it is but it might be wrong

7 0
3 years ago
Increase 120cm by 24%. Please help. Homework due tomorrow. Thanks
bixtya [17]
The answer is 148.8
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3 years ago
If f(–5) = 0, what are all the factors of the function f(x)=x^3-19x+30? Use the Remainder Theorem.
nirvana33 [79]
A. (x-2)(x+5)(x-3) is the correct answer to this question : )
8 0
3 years ago
Read 2 more answers
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