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AlexFokin [52]
3 years ago
14

What is the dimension of the hypotenuse of the accompanying right triangle?

Mathematics
1 answer:
Neko [114]3 years ago
5 0

It's not possible to know, because you're not letting us see
the accompanying right triangle.

You might be interested in
I need help to solve<br> 5×-2y=-2<br> -×+4y=4
kotegsom [21]

Answer:

x=3 and y=4x=3 and y=4

Step-by-step explanation:

x=3 and y=4

7 0
3 years ago
You randomly survey students about year-round school. The results are shown in the graph.
Sergio [31]

Answer:

27% and 37%

Step-by-step explanation:

Percentage of students who oppose the year-round school = 68%

Percentage of students who support the year-round school = 32%

Margin of error = ± 5%

We have to set up the absolute valued equation to find the range(least and greatest) percentages of students who could be in favor of year-round school.

Since, the percentage of students who support the year-round school is 32% and the margin of error is 5%, this means, the difference between 32% and the least and greatest possible percentages is 5%. It can be either +5% or -5%

This thing can be expressed as absolute valued equation as:

| x - 32 | = 5

Here x represents the least and greatest percentages.

Expanding the equation, we can write:

x - 32 = -5                or                x - 32 = 5

x = -5 + 32                or               x = 5 + 32

x = 27%                                       x= 37%

This means the least percentage of students who be in favor is 27% and the greatest percentage of students is 37%.

6 0
3 years ago
The following formula for the sum of the cubes of the first n integers is proved in Appendix E. Use it to evaluate the limit in
Marina86 [1]

Answer:

\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2})

And when we apply the limit we got that:

\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2}) =1

Step-by-step explanation:

Assuming this complete problem: "The following formula for the sum of the cubes of the first n integers is proved in Appendix E. Use it to evaluate the limit . 1^3+2^3+3^3+...+n^3=[n(n+1)/2]^2"

We have the following formula in order to find the sum of cubes:

\lim_{n\to\infty} \sum_{n=1}^{\infty} i^3

We can express this formula like this:

\lim_{n\to\infty} \sum_{n=1}^{\infty}i^3 =\lim_{n\to\infty} [\frac{n(n+1)}{2}]^2

And using this property we need to proof that: 1^3+2^3+3^3+...+n^3=[n(n+1)/2]^2

\lim_{n\to\infty} [\frac{n(n+1)}{2}]^2

If we operate and we take out the 1/4 as a factor we got this:

\lim_{n\to\infty} \frac{n^2(n+1)^2}{n^4}

We can cancel n^2 and we got

\lim_{n\to\infty} \frac{(n+1)^2}{n^2}

We can reorder the terms like this:

\lim_{n\to\infty} (\frac{n+1}{n})^2

We can do some algebra and we got:

\lim_{n\to\infty} (1+\frac{1}{n})^2

We can solve the square and we got:

\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2})

And when we apply the limit we got that:

\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2}) =1

3 0
3 years ago
Help please.... I have got this wrong 2xs only once chance left
Jet001 [13]

Answer:

a: 5x-1 = -6

b: 5x-1 = -6

        +1   +1

5x = -5

divide

x = -1

7 0
3 years ago
Find cos(B) in the triangle.<br> Choose 1 answer: 8/17
gavmur [86]

Answer:

8 / 17

Step-by-step explanation:

So cosine is adjacent ÷ hypotenuse.

Adjacent = 8

Hypotenuse = 17

8 / 17

7 0
4 years ago
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