(-5C^2)^3-(5c)^6
-125C^5 - 15625c^6
A parallel line has the same slope as the original line. So in this case the slope of the line is also 3/4. Now how do we know if it intersects the point? We need to adjust the y intercept.
Currently, we know the equation of the line is y= 3/4 x + b, where b is the thing we are looking for. We also have a point, which supplies the x and y. Plug that in and solve for b
-2 = (3/4)*(12) + b
You'll get b= -11
So the equation of the parallel line intersecting the point given is y= 3/4x -11.
I am assuming that the slope is 3/4 based on the way you formatted the original equation, but it's the same steps if the slope is different.
Answer:
Step-by-step explanation:
The square in the middle has a length and width of 3, so multiply. <u>9</u>.
All of the triangles have a base of 3 and a height of 2. The area equation for triangles is
So base*height is 6. Divide that by 2 or multiply by 1/2.
You get 3. There are 4 triangles, so multiply <em>that</em> by 4. <u>12</u>.
Add 12 and 9 together, and you get:
I hope this helps!
So to solve for y, subtract 108 from each side.
The equation becomes -y=126
Since you don't want y to be negative then divide each side by -1 this will flip all of the signs (positives become negative and vice versa) without changing the number.
So the equation is now y= -126
