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xxMikexx [17]
2 years ago
5

What is the image point of (5,-6)(5,−6) after the transformation r_{\text{y-axis}}\circ T_{-4,0}r

Mathematics
1 answer:
Brums [2.3K]2 years ago
5 0

The <em>image</em> point of <em>P(x,y) =</em><em> (5, -6)</em> after applying a <em>horizontal</em> reflection is <em>P'(x,y) =</em><em> (1, -6)</em>.

<h3>How to apply a rigid transformation in a point on a Cartesian plane</h3>

In geometry, a <em>rigid</em> transformation is a transformation applied onto a <em>geometric</em> object such that <em>Euclidean</em> distance in every point of it is conserved. Translations are examples of <em>rigid</em> transformations and are defined by this formula:

<em>P'(x,y) = P(x,y) + T(x,y)</em>   (1)

Where:

  • <em>P(x,y)</em> - Original point
  • <em>T(x,y)</em> - Translation vector
  • <em>P'(x,y)</em> - Image point

If we know that <em>P(x,y)</em><em> = (5, -6)</em> and <em>T(x,y)</em><em> = (-4, 0)</em>, then the image point is:

<em>P'(x,y) = (5, -6) + (-4, 0)</em>

<em>P'(x,y) = (1, -6)</em>

The <em>image</em> point of <em>P(x,y) =</em><em> (5, -6)</em> after applying a <em>horizontal</em> reflection is <em>P'(x,y) =</em><em> (1, -6)</em>. \blacksquare

<h3>Remark</h3>

Statement is incorrect and poorly formatted. Correct form is shown below:

<em>What is the image point of </em><em>(x, y) = (5, -6)</em><em> after the transformation of translating horizontally the point -4 units to the y-axis?</em>

To learn more on rigid transformations, we kindly invite to check this verified question: brainly.com/question/1761538

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