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Paul [167]
3 years ago
14

Helppp plzzzzzzz?????

Mathematics
2 answers:
Nezavi [6.7K]3 years ago
4 0
Answer is B
C is incorrect
Viktor [21]3 years ago
3 0
I believe the answer is C. 


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Serena wants to create snack bags for a trip she is going on. She has 6 granola bars and 10 pieces of dried fruit. If the snack
Rainbow [258]

Answer:

2

Step-by-step explanation:

Given the question :

Serena wants to create snack bags for a trip she is going on. She has 6 granola bars and 10 pieces of dried fruit. If the snack bags should be identified without any food leftover, what is the greatest number of snack bags Serena can make?

Number of granolas = 6

Number of dried fruits = 10

Since the snackbag is to be designed in such a way that there should be no food leftover, the greatest number of snack bags Serena can make could be obtained by getting the highest common factor of (6 and 10)

____6____10

2___3____5

Here, the highest common factor of 6 and 10 is 2

Hence, the greatest number of snack bags she can make is 2.

5 0
3 years ago
What is 244 divided by 60 with remainders
Troyanec [42]
244 divided by 60 = 4.0666
3 0
2 years ago
Read 2 more answers
How much simple interest is earned on an investment of 1,250 if the money is invested for 5 years at an annual interest rate of
Alekssandra [29.7K]
<h3>Answer:  $281.25</h3>

Work Shown:

i = P*r*t

i = 1250*0.045*5

i = 281.25

8 0
2 years ago
Simplify 2^9/2^6<br><br> A. 2^15<br><br> B. 4^3<br><br> C. 4^-3<br><br> D. 2^3
nirvana33 [79]

Answer:

B

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What are the number of integral solutions of the equation 2x+2y+z=20 such that x&gt;=0 , y&gt;=0 , z&gt;=0?
zaharov [31]
2x+2y+z=20\\&#10;z=\dfrac{20}{2x+2y}\\&#10;z=\dfrac{10}{x+y}

Now, for z to be an integer, the sum x+y must be a divisor of 10. 
It has to be a positive divisor since z≥0. Also x≠y.

x+y=1 \\&#10;x=1-y\\&#10;
x≥0 and y≥0 so y can be equal to either 0 or 1. There are 2 solution in this case.

x+y=2\\&#10;x=2-y\\
In this case, y can be equal to 0,1, or 2, but for y=1 ⇒ x=1, so there are two solutions.

x+y=5\\&#10;x=5-y
y can be 0,1,2,3,4 or 5 - 6 solutions

x+y=10\\&#10;x=10-y
y can be 0,1,2,3,4,5,6,7,8,9,10, but for y=5 ⇒ x=5, so 10 solutions.

2+2+6+10=20 solutions in total.
6 0
3 years ago
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