The correct answer is: C) Mycobacterium tuberculosis.
Tuberculosis is an infectious disease that most commonly affects lungs. Mycobacterium tuberculosis is a small, aerobic, nonmotile bacillus type of bacteria responsible for this disease.
There are two forms of tuberculosis:
• Latent-without symptoms
• Active-with symptoms such as chronic cough, fever, sweats, weight loss..
People with active tuberculosis can spread it by the air while they cough, spit, speak, or sneeze.
So I don’t see answer choices here, but your answer is 50% of the offspring will be homozygous dominant with RR, and 100% of them will carry a homozygous dominant gene of Rr
If you take the two sets and put them into a punnett square, it would look like this (image attached):
When the two sets of alleles are crossed, you would end up with half of your pairs being fully dominant (RR), and the other half being dominant while containing a recessive gene (Rr). Since there’s only one recessive gene in these pairs, it gets overridden and the pair itself is dominant.
So your answer is 50% will be homozygous dominant with RR!
No just like dogs they differ in some ways
Giddy UP
The answer is B, matrix of the mitochondria
This is an example of Precursor gene regulation (protein translation) type of eukaryotic gene regulation.
<u>Explanation:</u>
The source which breakdown proteins into smaller amino acid is pepsin and generated as top cells within stomach lining or membrane, responsible for pepsinogen emission inside stomach. It is represented as zymogen having an extra 44 amino acids linkage as its primary structure. Hydrochloric acid (HCl) releases this zymogen which is emitted from the parietal cells in the stomach lining.
Once food is consumed, the hormone gastrine and the vagus nerve cause the secretion of both pepsinogen and HCl from the stomach lining. Hydrochloric acid induces an acidic environment that allows pepsinogen to unfold in an autocatalytic manner and thus generates pepsin the active form.