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SVETLANKA909090 [29]
2 years ago
12

TAKE TIME AND HELP FOR BRAINLIEST!

Mathematics
2 answers:
Brilliant_brown [7]2 years ago
8 0

Answer:

I used Desmos to graph your requirements, and i took a screenshot of the graph. Credit to Desmos for the great graphing system.

Step-by-step explanation:

LUCKY_DIMON [66]2 years ago
7 0

Answer:

see image

Step-by-step explanation:

Anytime you see f(x) that just means y.

So f(x)=5 just means

y = 5

Anytime you have an equation to graph that is in the format

"y= anumber", that is a Horizontal line. So the first piece of your graph is the horizontal line thru 5. But also that's only for x>=3. It includes the 3 with the "or=to" underline. So the point must be a solid filled-in point. (Some weird books or teachers use a [ square bracket.) Same logic works for the second piece of the function. f(x) = -6 is the same as y= -6 and is a horizontal line thru -6. But the point at (3, -6) is an Open dot! See image.

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Two photos were taken of a car.
LenKa [72]

Answer:

14.4 m / s

Step-by-step explanation:

=distance between the car

=0.8 × 9

=7.2m

=time taken

=0.5s

=speed

=distance/time

=7.2m/0.5s

=14.4 m / s

4 0
2 years ago
A heavy rope, 50 ft long, weighs 0.6 lb/ft and hangs over the edge of a building 120 ft high. Approximate the required work by a
Anastasy [175]

Answer:

Exercise (a)

The work done in pulling the rope to the top of the building is 750 lb·ft

Exercise (b)

The work done in pulling half the rope to the top of the building is 562.5 lb·ft

Step-by-step explanation:

Exercise (a)

The given parameters of the rope are;

The length of the rope = 50 ft.

The weight of the rope = 0.6 lb/ft.

The height of the building = 120 ft.

We have;

The work done in pulling a piece of the upper portion, ΔW₁ is given as follows;

ΔW₁ = 0.6Δx·x

The work done for the second half, ΔW₂, is given as follows;

ΔW₂ = 0.6Δx·x + 25×0.6 × 25 =  0.6Δx·x + 375

The total work done, W = W₁ + W₂ = 0.6Δx·x + 0.6Δx·x + 375

∴ We have;

W = 2 \times \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= 2 \times \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 750

The work done in pulling the rope to the top of the building, W = 750 lb·ft

Exercise (b)

The work done in pulling half the rope is given by W₂ as follows;

W_2 =  \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 562.5

The work done in pulling half the rope, W₂ = 562.5 lb·ft

6 0
2 years ago
A lumberjack can cut a log into 5 pieces in 20 minutes. How long does it take to cut a log of the same size and shape into 7 pie
Nitella [24]

Answer:

28minutes

Step-by-step explanation:

Use this simple trick, it can be used almost everywhere

Time taken pieces

20mins 5

? 7

An x shape is always multiply and straight line is divide

So (7 x 20) ÷5

If u still don't understand, just comment again

8 0
2 years ago
Help me please,Thanks
crimeas [40]
I think its 36, i'm not sure.
8 0
3 years ago
19-20<br> Please<br><br> Thank u
yan [13]
19-20 = -1 u have to subtract left from tight <span />
7 0
3 years ago
Read 2 more answers
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