What is the correct format to use when inserting a date in Excel?

Oxnard Casualty wants to ensure that their e-mail server has 99.98 percent reliability. They will use several independent server

sattari [20]

Answer:

The smallest number of servers required is 3 servers

Explanation:

Given

$Reliability = 99.98\%$

$Individual Servers = 95\%$

Required

Minimum number of servers needed

Let p represent the probability that a server is reliable and the probability that it wont be reliable be represented with q

Such that

$p = 95\%\\$

It should be noted that probabilities always add up to 1;

So,

$p + q = 1$ '

Subtract p from both sides

$p - p + q = 1 - p$

$q = 1 - p$

Substitute $p = 95\%\\$

$q = 1 - 95\%$

Convert % to fraction

$q = 1 - \frac{95}{100}$

Convert fraction to decimal

$q = 1 - 0.95$

$q = 0.05$

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To get an expression for one server

The probabilities of 1 servers having 99.98% reliability is as follows;

$p = 99.98\%$

Recall that probabilities always add up to 1;

So,

$p + q = 1$

Subtract q from both sides

$p + q - q = 1 - q$

$p = 1 - q$

So,

$p = 1 - q = 99.98\%$

$1 - q = 99.98\%$

Let the number of servers be represented with n

The above expression becomes

$1 - q^n = 99.98\%$

Convert percent to fraction

$1 - q^n = \frac{9998}{10000}$

Convert fraction to decimal

$1 - q^n = 0.9998$

Add $q^n$ to both sides

$1 - q^n + q^n= 0.9998 + q^n$

$1 = 0.9998 + q^n$

Subtract 0.9998 from both sides

$1 - 0.9998 = 0.9998 - 0.9998 + q^n$

$1 - 0.9998 = q^n$

$0.0002 = q^n$

Recall that $q = 0.05$

So, the expression becomes

$0.0002 = 0.05^n$

Take Log of both sides

$Log(0.0002) = Log(0.05^n)$

From laws of logarithm $Loga^b = bLoga$

So,

$Log(0.0002) = Log(0.05^n)$ becomes

$Log(0.0002) = nLog(0.05)$

Divide both sides by $Log0.05$

$\frac{Log(0.0002)}{Log(0.05)} = \frac{nLog(0.05)}{Log(0.05)}$

$\frac{Log(0.0002)}{Log(0.05)} = n$

$n = \frac{Log(0.0002)}{Log(0.05)}$

$n = \frac{-3.69897000434}{-1.30102999566}$

$n = 2.84310893421$

$n = 3 (Approximated)$

Hence, the smallest number of servers required is 3 servers

6 0

3 years ago

Plato :

ddd [48]

Answer:

filler content

Explanation:

Isabel must use some sort of filler content while creating a wireframe that she is up with. For the banner, she can make use of the placeholder, and for the text, she can make use of the lorem ipsum. Also, if the wireframe is low fidelity then only she can use above. And if the wireframe is high fidelity then she should use the original banner and text.

3 0

3 years ago

Read 2 more answers

Which of the following factors wouldn't change an account's optimization score?

MatroZZZ [7]

Answer:

Renaming Campaigns

Explanation:

Based on the information provided within the question it can be said that the factor that wouldn't change this would be Renaming Campaigns. This is because an account's optimization score is an estimate of how well the account/campaign will perform in the near future. Changing the name will not change this score since the campaign is still following the same strategy and therefore the estimates will be the same.

8 0

3 years ago

Use the distributive property to expand the following expression. (9m - 6)7

Nady [450]

(9m - 6)7
(9m × 7) - (6 × 7)
63m - 42

7 0

3 years ago

Read 2 more answers

A teacher has five students who have taken four tests. The teacher uses the following grading scale to assign a letter grade to

AlladinOne [14]

Answer:

#include <iostream>

using namespace std;

int main()

{

const int numofStudents = 5;//number of students

const int numofTests = 2;//number of tests taken by students

const int grade = 5;//number of grades available

char letter[grade] = { 'A','B','C','D','F' };

double table[numofStudents][numofTests];//defining 2darray with names and scores

string names[numofStudents];//storing names of students

for (int num = 0; num < numofStudents; num++)//storing names and scores of students

{

cout << "Enter student's name: ";

cin >> names[num];

for (int test = 0; test < numofTests; test++)//scores loop

{

cout << "Enter the test score: ";

cin >> table[num][test];

if (table[num][test] < 0 || table[num][test]>100)//input validation

{

cout << "Invalid input. Try again" << endl;

cin >> table[num][test];//input again

}

for (int i = 0;i < numofStudents;i++)//calculating averages and grades

{

int sum = 0;

cout << "Test scores for " << names[i] << ": " << endl;

for (int j = 0;j < numofTests;j++)

{

cout << table[i][j] << " ";

sum += table[i][j];//summing scores

}

cout << endl;

float average = (float)sum / numofTests;//calculating the average

cout << "Making an average of: "<< average;

if (average <= 100 && average >= 90)//assigning a grade

{

cout << " and has received an " << letter[0];

}

else if (average <= 89 && average >= 80)

{

cout << " and has received a " << letter[1];

}

else if (average <= 79 && average >= 70)

{

cout << " and has received a " << letter[2];

}

else if (average <= 69 && average >= 60)

{

cout << " and has received a " << letter[3];

}

else if (average <= 59 && average >= 0)

{

cout << " and has received an " << letter[4];

}

else

{

cout << "Invalid scores entered." << endl;

}

cout << endl;

}

return 0;

}

Explanation:

We first define the number of students, number of tests and number of grades available for assignments. We then fill in the 2D array of students names and their scores making sure assigning more than 100 and less than 0 is not allowed. We then sum the scores and retrieve an average. Using the average, a letter grade is assigned to that individual.

6 0

3 years ago