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Valentin [98]
2 years ago
11

Consider this figure. 11 1/2 in 10 in 20 in​

Mathematics
1 answer:
velikii [3]2 years ago
6 0
OK 11 divaide 20= 220 divaide 10 = 2.200
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2/3* (1/3+3 1/4 help pls now
ale4655 [162]

Answer:

43/18

Step-by-step explanation:

2/3(1/3+ 3 1/4)

  • First solve parenthesis.

2/3(1/3+ 3 1/4)

find the lowest common denominator (12) to add the two fractions.

1/3= 4/12;  

3 1/4= 13/4 = 39/12

4/12+ 39/12= 43/12

2/3(43/12)

  • Then multiply the fractions.

2/3(43/12)

Numerator: 2*43= 86

Denominator: 3*12= 36

86/36

  • Last simplify your fraction.

43/18 or 2 7/18

4 0
3 years ago
Evaluate x ÷ y for x = 3 and y = 12.
eduard

Answer:

1/4 or 0.25

Step-by-step explanation:

Lets plug x and y into the equation. We now have 3/12, which would be equal to 1/4 or 0.25

6 0
3 years ago
PLEASE HELP!!!!! Write the absolute value inequality in the form
Elena-2011 [213]

Answer:

|x - 1 |> 6,

Step-by-step explanation:

First we find the distance between the two points

-5 to 7

7 - -5 =7+5 = 12

We find 1/2 that distance

12/2 = 6

So we are looking for a greater-than inequality  because we are looking for the outsides because we want a less than and a greater than

|x - b |> c,

The center is 6 to that is c

|x - b |> 6,

To find the value of b

Let x = 7

7 -b =6

b=1

|x - 1 |> 6,

We can check by using -5

|-5 - 1 |> 6,

7 0
2 years ago
Read 2 more answers
The nutrition label for Oriental Spice Sauce states that one package of sauce has 1100 milligrams of sodium. To determine if the
lora16 [44]

Answer:

We conclude that the sodium content is same as what the nutrition label states.

Step-by-step explanation:

We are given that the nutrition label for Oriental Spice Sauce states that one package of sauce has 1100 milligrams of sodium.

The FDA randomly selects 40 packages of Oriental Spice Sauce and determines the sodium content. The sample has an average of 1088.64 milligrams of sodium per package with a sample standard deviation of 234.12 milligrams.

<u><em /></u>

<u><em>Let </em></u>\mu<u><em> = average sodium content.</em></u>

So, Null Hypothesis, H_0 : \mu = 1100 milligrams      {means that the sodium content is same as what the nutrition label states}

Alternate Hypothesis, H_A : \mu \neq 1100 milligrams      {means that the sodium content is different from what the nutrition label states}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about population standard deviation;

                    T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n}}}  ~ t_n_-_1

where, \bar X = sample average sodium content = 1088.64 milligrams

            s = sample standard deviation = 234.12 milligrams

            n = sample of packages of Oriental Spice Sauce = 40

So, <u><em>test statistics</em></u>  =  \frac{1088.64-1100}{\frac{234.12}{\sqrt{40}}}  ~ t_3_9

                              =  -0.307

The value of z test statistics is -0.307.

<em>Since, in the question we are not given the level of significance so we assume it to be 5%. </em><em>Now, at 0.05 significance level the t table gives critical values of -2.0225 and 2.0225 at 39 degree of freedom for two-tailed test.</em><em> </em>

<em>Since our test statistics lies within the range of critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which </em><em><u>we fail to reject our null hypothesis</u></em><em>.</em>

Therefore, we conclude that the sodium content is same as what the nutrition label states.

3 0
3 years ago
Andrew was making a science project for school. He worked for 6.6 hours the first week, 2.75 hours the second week, and 4.4 hour
fiasKO [112]

Answer:

Step-by-step explanation:

its wierd but 2.22

8 0
3 years ago
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