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8090 [49]
2 years ago
13

Can someone help me with this question please and thank you.

Mathematics
1 answer:
Alexxandr [17]2 years ago
4 0

Answer:

its porpotional

Step-by-step explanation:

hope this helps

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you flip a coin and draw a marble at random from a bag containing two purple marbles and one white marble . what is the probabil
yawa3891 [41]

Answer:

1/3 probability

Step-by-step explanation:

The probability that you flip heads is 1/2, one heads out of two possible (heads and tails).

The probability that you draw a purple marble is 2/3, two purples and three total (2 p +1 w).

To find the probability of both happening, multiply the probabilities together:

(1/2) * (2/3) = (2/6) = (1/3)

8 0
2 years ago
Need a real answer please
xz_007 [3.2K]

Answer:

Restate the question please?

Step-by-step explanation:

7 0
3 years ago
Instructions: Match each equations with correct type of event.
Mazyrski [523]

The question is incomplete. Below you will find the missing contents.

The correct match of events with order are,

  • P(A)P(B|A) - Dependent event
  • P(A)+P(B) - Mutually exclusive events
  • P(A and B)/P(A) - Conditional events
  • P(A) . P(B) - Independent Events
  • P(A)+P(B) -P(A and B) - not Mutually exclusive events.

When two events A and B are independent then,

P(A and B)=P(A).P(B)

when A and B are dependent events then,

P(A and B) = P(A) . P(B|A)

When two events A and B are mutually exclusive events then,

P(A and B)=0

So, P(A or B) = P(A) + P(B) - P(A and B) = P(A) + P(B)

P(A) + P(B) = P(A or B)

When events are not mutually exclusive then the general relation is,

P(A or B) = P(A) + P(B) - P(A and B)

If the probability of the event B conditioned by A is given by,

\mathrm{P(B|A)=\frac{P(A~and~B)}{P(A)}}

Hence the correct match are -

  • \mathrm{P(A)P(B|A)\rightarrow} Dependent event
  • \mathrm{P(A)+P(B)}\rightarrow Mutually exclusive events
  • \mathrm{\frac{P(A ~and ~B)}{P(A)}\rightarrow} Conditional events
  • \mathrm{P(A) . P(B)\rightarrow} Independent Events
  • \mathrm{P(A)+P(B) -P(A ~and ~B)\rightarrow} not Mutually exclusive events.

Learn more about Probability of Events here -

brainly.com/question/79654680

#SPJ10

5 0
1 year ago
Production times are evenly distributed between 8 and 15.8 minutes and production times are never outside of this interval. What
dezoksy [38]

Answer:

29.49% probability that a production time is between 9.7 and 12 minutes

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X between c and d, in which d is greater than c, is given by the following formula.

P(c \leq X \leq d) = \frac{d - c}{b-a}

Production times are evenly distributed between 8 and 15.8 minutes and production times are never outside of this interval.

This means that a = 8, b = 15.8

What is the probability that a production time is between 9.7 and 12 minutes?

d = 12, c = 9.7.

So

P(c \leq X \leq d) = \frac{d - c}{b-a}

P(9.7 \leq X \leq 12) = \frac{12 - 9.7}{15.8 - 8} = 0.2949

29.49% probability that a production time is between 9.7 and 12 minutes

5 0
3 years ago
5p + 6 = -4p - 8<br> Solve for p
Fofino [41]
9p=-14

p=-14/9 is the answer to the problem

5p+4p+6= -8
9p= -8-6
9p=-14
p= -14/9
7 0
2 years ago
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