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natta225 [31]
2 years ago
5

How is geeking out related to the concept of social capital?

Computers and Technology
1 answer:
vodka [1.7K]2 years ago
3 0

Answer:

It relates to social relationships and social structures. It involves people knowing each other and having positive relationships based on trust, respect, kindness, ect.

Explanation:

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Answer all of the questions,
Phantasy [73]

Answer:

sry but I don't know the answer

5 0
2 years ago
Question 1. (50 points) 1.Write a program that computes information related to a sequence of entries regarding age of customers.
schepotkina [342]

Answer:

The solution code is written in Python 3:

  1. count = 0
  2. totalAge = 0
  3. group1_count = 0    #age < 10
  4. group2_count = 0    #age 10 - 20
  5. group3_count = 0    #age 20 - 40
  6. group4_count = 0    #age > 40
  7. group1_total = 0    #subtotal age <= 10
  8. group2_total = 0    #subtotal age 11 - 20  
  9. group3_total = 0    #subtotal age 21 - 40  
  10. group4_total = 0    #subtotal age > 40
  11. age = int(input("Input an age: "))
  12. youngest = age
  13. oldest = age
  14. while(age != -1):
  15.    count += 1
  16.    totalAge += age
  17.    
  18.    if(age <= 10):
  19.        group1_count += 1
  20.        group1_total += age
  21.    elif(age <= 20):
  22.        group2_count += 1
  23.        group2_total += age
  24.    elif(age <= 40):
  25.        group3_count += 1
  26.        group3_total += age
  27.    else:
  28.        group4_count += 1
  29.        group4_total += age
  30.    if(youngest > age):
  31.        youngest = age  
  32.    
  33.    if(oldest < age):
  34.        oldest = age  
  35.    age = int(input("Input an age: "))
  36.    
  37. totalCustomer = count  
  38. avgAge = totalAge / count  
  39. rangeAge = oldest - youngest  
  40. avgAgeGroup1 = group1_total / group1_count  
  41. avgAgeGroup2 = group2_total / group2_count  
  42. avgAgeGroup3 = group3_total / group3_count  
  43. avgAgeGroup4 = group4_total / group4_count  
  44. print("The total number of customers: " + str(totalCustomer))
  45. print("Total number of customer in Group 1 (<=10): " + str(group1_count))
  46. print("Total number of customer in Group 2 (11 - 20): " + str(group2_count))
  47. print("Total number of customer in Group 3 (21 - 40): " + str(group3_count))
  48. print("Total number of customer in Group 4 (> 40): " + str(group4_count))
  49. print("Average age for all customer: " + str(avgAge))
  50. print("Youngest age: " + str(youngest))
  51. print("Oldest age: " + str(oldest))
  52. print("The range of age: " + str(rangeAge))
  53. print("Average age for group 1 (<=10): " + str(avgAgeGroup1))
  54. print("Average age for group 2 (11 - 20): " + str(avgAgeGroup2))
  55. print("Average age for group 3 (21 - 40): " + str(avgAgeGroup3))
  56. print("Average age for group 4 (> 40): " + str(avgAgeGroup4))

Explanation:

Firstly, create the counter variables (e.g. count, group1_count, group2_count etc ) to track the total number of customer and number in each age group. Besides, create variables to hold the value of total of age and sub-total of each age group (Line 1 - 10). We presume there are only four age groups.

Next, prompt user to input the first age (Line 12)

Create variable youngest and oldest to track the lowest and highest age (Line 13 -14). At the moment, set the first input age as value of youngest and oldest.

Create a while loop with sentinel value  -1 (Line 16). Within the loop, track the customer occurrence by incrementing counter variables by one (Line 17, 21, 24, 27 & 30). At the same time, add the current input age to totalAge and to group total (Line 18, 22, 25, 28, & 31).

If the current youngest value is bigger than the current input age, we set the current age to youngest (Line 33- 34).

If the current oldest value is smaller than the current input age, we set the current age to oldest (Line 36- 37).

After terminating the loop with -1, calculate the average age for all customers and for each age group and the range of age (Line 42- 48)  

At last, display all the required calculation results using print function (50 - 62)

7 0
2 years ago
1D Array Assignment Outcome: Student will demonstrate the ability to use a one-dimensional array. Student will demonstrate the a
sukhopar [10]

Answer:

Program to this question as follows:

program:

import java.util.*; //import package for user input

public class Main  //defining class  

{

public static void main(String[] as)//defining main function

{//defining integer array

int [] num = new int[113];  

boolean find_in = false; //defining boolean variable

int [] counts = new int[101];//defining integer array

int y, tem = 0, counter = 0,in=0,x,find; //defining integer variable

Scanner ox= new Scanner(System.in); //creating Scanner class Object

while(counter <= 112) //loop to check condition

{

num[counter++] = generateRandomNumber(); //using array to hold random function value.  

}

System.out.println("The array:"); //message

for(x = 0; x < 112; x++) // loop to count the value

{

if(x != 0 && x % 9 == 0) // if block to chek value

System.out.println(); // print  

else

System.out.print(num[x] + " "); // print array

}

// sort in ascending order

Arrays.sort(num); //using sort method

System.out.print("\n\nThe array in sorted order:"); // print value

for( x = 0; x < num.length; x++) // loop uses if block to check value is divisiable by 9  

{

if(x % 9 == 0) //check condition  

System.out.println(); // print  

else

System.out.print(num[x] + " "); // print array

}

// search for a number

System.out.print("\n\nEnter a number to search: "); // print message

find= ox.nextInt(); // input number by user

for(x= 0;x< num.length;x++) //loop to count values

{

if(num[x] == find) //check value

{

find_in = true; //change value

in= x;

break; //using break keyword

}

}

if(find_in)  //find value

System.out.println(find + " is found at index " + in); // print location

else

System.out.println("Not found"); //message

// display count of each numbers

System.out.println("Count of each numbers:"); //message

for(y = 1; y< num.length; y++) // loop to store element in counts array  

{

tem = num[y]; //hold value

counts[tem]++; //increment value

}

for(x = 1; x< counts.length; x++) //loop to print value

{

System.out.println(x + ": " + counts[x]); // print value

}

// average of the numbers in the array

for(x = 0; x < num.length; x++) // loop to calculate sum and average

{

sum += num[x]; //calculate sum

}

avg = (sum / 100); // calculate avg

System.out.println("\nThe average of the numbers in the array: " + avg);

// highest number in the array

int high= num[0]; //find number

for(x= 0;x < num.length;x++)

{

if(num[x] > high)

high = num[x]; //hold value of highest Number

}

System.out.println("\nThe highest number is: " + high); //print value

int low = num[0]; // defining variable for lowest number

for(x= 0; x < num.length - 1; x++) // loop to calculate lowest number

{

if(num[x] < low) //condition for lowest number

low = num[x]; //hold lowest number

}

System.out.println("\nThe lowest number is: " + low); //print value

}

public static int generateRandomNumber() //defining function  

{

Random ra = new Random(); //creating Random function Object

return (ra.nextInt(100)+ 1); //input and return value

}

}

Output:

the output of the given code is display in image

Explanation:

In the above program, an array is declared that uses a random function to input the number, in the next step the sort function is used, that sorted all array elements, in the next step the scanner class is used, that input the number form the user ends and pass search in the sorted array.

  • After searching the average of array elements is calculated. In this array we calculate the highest and lowest number of the array to print all the values the print method is used.
  • At the last, the rand method is used that generates the random number for the array and passes into a num array that prints the values.

7 0
3 years ago
Can someone that been helping me answer one more question for please and thx
Gnom [1K]

Answer:

D

Explanation:

Federal Tax, not state

5 0
3 years ago
What is a focus of Accenture's point of view on blockchain in the marketplace?
Ipatiy [6.2K]

Answer:

enabling clients to store all their data, documents, and employee information on blockchain. accumulating the most data from wherever possible and building a comprehensive data lake.

Explanation:

4 0
2 years ago
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