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grandymaker [24]

2 years ago

10

Manny drew a scale diagram of his classroom. His real classroom is 20 feet wide. Manny's drawing is 4 centimeters (cm) wide. Wha

t is the scale factor of the drawing?

1 answer:

Mariulka [41]2 years ago

5 0

Answer:

1 cm : 5 feet

Step-by-step explanation:

4 cm : 20 feet

1 cm : 5 feet

20 has been divided by 4.

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A baseball team won 20 games and lost 10 games. What percent of the games did the team win?

wel

Answer:

66%

Step-by-step explanation:

- First, add 20 + 10 = 30. This will give you the total amount of games.

- Now, make this into a fraction for won games. This should be 20/30.

- Next, take 20/30 and simplify it. You should get 2/3 as a fraction.

- Now, take 2 and divide by 3. (2/3) You should get .66 repeating. This is equal to 66%.

- Therefore 66% is the answer.

- Hope this helps! If you need a further explanation please let me know.

4 0

3 years ago

Read 2 more answers

Every summand of an expression is called a???

cricket20 [7]

Answer:

I think it's called a term.

Hope this helps :)

4 0

2 years ago

PLAASE HELP ME! I will make BRAINIEST

Readme [11.4K]

Answer: Answer is the steps.

Step-by-step explanation:

The table of with the values

x y

0 3

1 1

2 -1

3 -3

It represents a linear function because as the y values decrease by 2 the x values increase by 1.

3 0

3 years ago

The time it takes for a planet to complete its orbit around a particular star is called the? planet's sidereal year. The siderea

BartSMP [9]

Answer:

(a) See below

(b) r = 0.9879

(c) y = -12.629 + 0.0654x

(d) See below

(e) No.

Step-by-step explanation:

(a) Plot the data

I used Excel to plot your data and got the graph in Fig 1 below.

(b) Correlation coefficient

One formula for the correlation coefficient is

$r = \dfrac{\sum{xy} - \sum{x} \sum{y}}{\sqrt{\left [n\sum{x}^{2}-\left (\sum{x}\right )^{2}\right]\left [n\sum{y}^{2} -\left (\sum{y}\right )^{2}\right]}}$

The calculation is not difficult, but it is tedious.

(i) Calculate the intermediate numbers

We can display them in a table.

<u> x </u> <u> y </u> <u> xy </u> <u> x² </u> <u> y² </u>

36 0.22 7.92 1296 0.05

67 0.62 42.21 4489 0.40

93 1.00 93.00 20164 3.46

433 11.8 5699.4 233289 139.24

887 29.3 25989.1 786769 858.49

1785 82.0 146370 3186225 6724

2797 163.0 455911 7823209 26569

<u>3675 </u> <u> 248.0 </u> <u> 911400 </u> <u>13505625</u> <u> 61504 </u>

9965 537.81 1545776.75 25569715 95799.63

(ii) Calculate the correlation coefficient

$r = \dfrac{\sum{xy} - \sum{x} \sum{y}}{\sqrt{\left [n\sum{x}^{2}-\left (\sum{x}\right )^{2}\right]\left [n\sum{y}^{2} -\left (\sum{y}\right )^{2}\right]}}\\\\= \dfrac{9\times 1545776.75 - 9965\times 537.81}{\sqrt{[9\times 25569715 -9965^{2}][9\times 95799.63 - 537.81^{2}]}} \approx \mathbf{0.9879}$

(c) Regression line

The equation for the regression line is

y = a + bx where

$a = \dfrac{\sum y \sum x^{2} - \sum x \sum xy}{n\sum x^{2}- \left (\sum x\right )^{2}}\\\\= \dfrac{537.81\times 25569715 - 9965 \times 1545776.75}{9\times 25569715 - 9965^{2}} \approx \mathbf{-12.629}\\\\b = \dfrac{n \sum xy - \sum x \sum y}{n\sum x^{2}- \left (\sum x\right )^{2}} - \dfrac{9\times 1545776.75 - 9965 \times 537.81}{9\times 25569715 - 9965^{2}} \approx\mathbf{0.0654}\\\\\\\text{The equation for the regression line is $\large \boxed{\mathbf{y = -12.629 + 0.0654x}}$}$

(d) Residuals

Insert the values of x into the regression equation to get the estimated values of y.

Then take the difference between the actual and estimated values to get the residuals.

<u> x </u> <u> y </u> <u>Estimated</u> <u>Residual </u>

36 0.22 -10 10

67 0.62 -8 9

93 1.00 -7 8

142 1.86 -3 5

433 11.8 19 - 7

887 29.3 45 -16

1785 82.0 104 -22

2797 163.0 170 - 7

3675 248.0 228 20

(e) Suitability of regression line

A linear model would have the residuals scattered randomly above and below a horizontal line.

Instead, they appear to lie along a parabola (Fig. 2).

This suggests that linear regression is not a good model for the data.

4 0

3 years ago

Suppose we deposit $73,000 into a savings account which compounds daily with 5% APY and we want to know how much the account wil

NARA [144]

Let
I1-------------> interest first day
I2-------------> interest second day

we know that
P0=$73000----------> initial amount

first day
I1=73000*(5%/100)*(1/365)-----------> I1=$10
P1=P0+I1------> $73000+$10-------- P1=$73010

second day
P1=$73010
I2=73010*(5%/100)*(1/365)-----------> I2=$10
P2=P1+I2------> $73010+$10-------- P2=$73020

the answer is $73020

3 0

3 years ago