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NISA [10]
2 years ago
13

What is the area of the composite figure? Enter your answer in the box. ______cm^2

Mathematics
1 answer:
Nitella [24]2 years ago
3 0

Answer:

  • 70 cm²

Step-by-step explanation:

<h3>Find the area of rectangle</h3>
  • 10*5 = 50 cm²
<h3>Find the area of triangle</h3>
  • 1/2*5*(18 - 10) = 20 cm²
<h3>Area of the figure is</h3>
  • 50 + 20 = 70 cm²
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Given that <span>v=234 3√p/w (cube root)
where </span><span> 
p is the horsepower of the car and
w is the weight (in pounds) of the car
v is the velocity in miles per hour

p = 1311 hp
w = 2744 lb
substitute the given value to the equation to solve for the velocity

v = 234 </span><span>3√(1311 / 2744)
v = 183 miles per hour is the velocity of a car at the end of a drag race.</span>
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What is the percentage of 198 from $3300 monthly ?
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Find the smallest relation containing the relation {(1, 2), (1, 4), (3, 3), (4, 1)} that is:
professor190 [17]

Answer:

Remember, if B is a set, R is a relation in B and a is related with b (aRb or (a,b))

1. R is reflexive if for each element a∈B, aRa.

2. R is symmetric if satisfies that if aRb then bRa.

3. R is transitive if satisfies that if aRb and bRc then aRc.

Then, our set B is \{1,2,3,4\}.

a) We need to find a relation R reflexive and transitive that contain the relation R1=\{(1, 2), (1, 4), (3, 3), (4, 1)\}

Then, we need:

1. That 1R1, 2R2, 3R3, 4R4 to the relation be reflexive and,

2. Observe that

  • 1R4 and 4R1, then 1 must be related with itself.
  • 4R1 and 1R4, then 4 must be related with itself.
  • 4R1 and 1R2, then 4 must be related with 2.

Therefore \{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(4,1),(4,2)\} is the smallest relation containing the relation R1.

b) We need a new relation symmetric and transitive, then

  • since 1R2, then 2 must be related with 1.
  • since 1R4, 4 must be related with 1.

and the analysis for be transitive is the same that we did in a).

Observe that

  • 1R2 and 2R1, then 1 must be related with itself.
  • 4R1 and 1R4, then 4 must be related with itself.
  • 2R1 and 1R4, then 2 must be related with 4.
  • 4R1 and 1R2, then 4 must be related with 2.
  • 2R4 and 4R2, then 2 must be related with itself

Therefore, the smallest relation containing R1 that is symmetric and transitive is

\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(2,1),(2,4),(3,3),(4,1),(4,2),(4,4)\}

c) We need a new relation reflexive, symmetric and transitive containing R1.

For be reflexive

  • 1 must be related with 1,
  • 2 must be related with 2,
  • 3 must be related with 3,
  • 4 must be related with 4

For be symmetric

  • since 1R2, 2 must be related with 1,
  • since 1R4, 4 must be related with 1.

For be transitive

  • Since 4R1 and 1R2, 4 must be related with 2,
  • since 2R1 and 1R4, 2 must be related with 4.

Then, the smallest relation reflexive, symmetric and transitive containing R1 is

\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(2,1),(2,4),(3,3),(4,1),(4,2),(4,4)\}

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Answer:

D. is your answer PICK D.

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1. What are the next two numbers in the sequence? 243,81,27, 9, _ , _
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Answer:

b

Step-by-step explanation:

dividing by 3

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