Question

Graham and hunter are circus performers. a cable lifts graham into the air at a constant speed of 1.5 ft/s. when graham’s arms are 18 ft above the ground, hunter, who is standing directly underneath graham, throws graham a ball as the cable continues to lift him higher. hunter throws the ball from a position 5 ft above the ground with an initial velocity of 24 ft/s. which system of equations can be used to model this situation? startlayout enlarged left-brace 1st row h = 18 1.5 t 2nd row h = 5 24 t minus 16 t squared endlayout startlayout enlarged left-brace 1st row h = 18 1.5 t 2nd row h = 5 24 t 16 t squared endlayout startlayout enlarged left-brace 1st row h = 18 1.5 t 2nd row h = 5 24 t endlayout startlayout enlarged left-brace 1st row h = 18 1.5 t minus 16 t squared 2nd row h = 5 24 t 16 t squared endlayout

Answer 1

Therefore, the system of equations that can be used to model this situation is h= 5 + 24t -16t^2.

What is the system of equation about?

The equations that were given in the system above are :

h = 18 + 1.5t

h = 5 + 24t - 16t^2

Note that:

The rate of Speed = distance divided by time

Since Speed = 1.5ft/s

Distance = 18ft

To know the time which was not given, the equation will be:

1.5ft/s = 18ft/t

1.5t=18

The equation to know height h= 18 + 1.5t

Since Graham moved another 5ft  along with a velocity of 24ft/s

Therefore, the system of equations that can be used to model this situation is h= 5 + 24t -16t^2 and as such, option A is correct.

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