Write a parallel and perpendicular equation that passes through the point (6,-2)?

Mathematics

1 answer:

Reptile [31]3 years ago

3 0

Answer:

y=x-8 and y=-x+4

Step-by-step explanation:

The slopes of the lines can be anything, as long as they are the opposite reciprocals of each other. Then you can plug in the point for x and y to solve for b in both lines (for y=mx+b where m is the slope)

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Solve kx+12=3kx for x

PilotLPTM [1.2K]

Answer:

$x=6/k$

Step-by-step explanation:

we have

$kx+12=3kx$

Solve for x

That means----> isolate the variable x

Subtract $kx$ both sides

$kx+12-kx=3kx-kx$

$12=2kx$

Divide by $2k$ both sides

$12/2k=2kx/2k$

$6/k=x$

Rewrite

$x=6/k$

3 0

4 years ago

Read 2 more answers

| -5 -(-8) | i need help with algabraic expression

MrMuchimi

-5 (-8) =3
And the absolute value of 3 is 3!

I hope this helps! & Let me know if you have any questions!

Mark this as Brainliest if you get a chance:)

7 0

3 years ago

9th grade alg 1 number 43 and work please!

Darya [45]

Answer:

The rule is y = -7x + 5

→ Other values of x;