Write a parallel and perpendicular equation that passes through the point (6,-2)?
1 answer:
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Hello from MrBillDoesMath!
Answer:
Perimeter = 60
Height = 18/5
Discussion:
The diagonals of a rhombus bisect each other at right angles. So a rhombus can be viewed as the union of 4 congruent right triangles, each with legs (1/2)*18 = 9 and (1/2) *24 = 12. See attachment. This gives a hypotenuse length of 15 so the Perimeter = 4 *c = 60.
The height ( = altitude) of a rhombus is
= area / length of base
= (1/2) ( (18) * 24) /c
= (1/2) ( 18 * 24) / 60
= 18/5
Thank you,
MrB
Answer:
x=35, y=21
Step-by-step explanation:
A way to rewrite the first equation is
after cross-multiplying, we get 3x=5y.
If we solve for one variable, we can substitute it into the other equation.
Let's solve for x.
3x=5y
x=(5/3)y
Now, we can substitute x=(5/3)y in the equation x+y=56.
(5/3)y+y=56
(8/3)y=56
y=21
Going back to x+y=56, we can now plug back in y, knowing that it is 21.
x+21=56
x=35.