2 years ago

Write a parallel and perpendicular equation that passes through the point (6,-2)?

Mathematics

1 answer:

Reptile [31]2 years ago

3 0

Answer:

y=x-8 and y=-x+4

Step-by-step explanation:

The slopes of the lines can be anything, as long as they are the opposite reciprocals of each other. Then you can plug in the point for x and y to solve for b in both lines (for y=mx+b where m is the slope)

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Given the equation square root of 8x plus 1 = 5, solve for x and identify if it is an extraneous solution. x = one fourth, solut

Rainbow [258]

Answer:

x=3, solution is not extraneous

Step-by-step explanation:

we have

$\sqrt{8x+1}=5$

Solve for x

squared both sides

$(\sqrt{8x+1})^2=5^2$

$8x+1=25\\8x=25-1\\8x=24\\x=3$

Verify

For x=3

$\sqrt{8(3)+1}=5$

$\sqrt{24+1}=5$

$\sqrt{25}=5$

$5=5$ -----> is true

therefore

x=3, solution is not extraneous

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3 years ago

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antiseptic1488 [7]

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liubo4ka [24]

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