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grandymaker [24]
3 years ago
15

Write a parallel and perpendicular equation that passes through the point (6,-2)?

Mathematics
1 answer:
Reptile [31]3 years ago
3 0

Answer:

y=x-8 and y=-x+4

Step-by-step explanation:

The slopes of the lines can be anything, as long as they are the opposite reciprocals of each other. Then you can plug in the point for x and y to solve for b in both lines (for y=mx+b where m is the slope)

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Dominic is signing up for a gym membership with a one-time fee to join and then a monthly fee to remain a member. The total cost
lana [24]

The slope intercept form is y=mx+b, and b represents the y-intercept. In the given equation C=45t+100, 100 is the y-intercept. It represents the one-time fee to join the gym membership.

8 0
3 years ago
Can you help me with this problem please
Over [174]

Remark

I think you want us to do both 3 and 4


Three

QR is 4 points going left from the y axis + 2 points going right from the y axis.

QR = 6 units long.


RT is 4 units above the x axis and 3 units below the x axis

RT = 7 units long


TS = 3 units. For this one you just go from T to S. The graph really helps you. You just need to count.


Problem 4

You need to find the area of the combined figure. You could do it as a trapezoid, which might be the easiest way. I'll do that first.


Area = (b1 + b2)*h/2


Givens

B1 = QR = 6

B2 = UT + TS = 6 + 3 = 9

h = RT = 7


Area

Area = (6 + 9)*7/2

Area = 15 * 7 / 2

Area = 52.5


Comment

You could break this up into a rectangle + a triangle

Find the area of QRTU and add the Area of triangle RTS


<em>Area of the rectangle </em>= L * W

L = RT = 7

W = QR = 6

Area = 7 *6 = 42


<em>Area of the triangle</em> = 1/2 * B * H

B = TS = 3

H = RT =7

Area = 1/2 * 3 * 7

Area = 1/2 * 21

Area = 10.5


Total Area = 42 + 10.5 = 52.5 Both answers agree.

3 0
3 years ago
Ver very simple one problem math please help
Tanzania [10]
That isn’t very simple
3 0
3 years ago
Read 2 more answers
XB is the angle bisector of ZAXC. MZAXB23А.BVхC с
neonofarm [45]

To obtain x, we can sum the angles < AQB and < BQC

=> 5X + 8X - 24

=> 13X -24

we are also told that that the sum of their angles is 80

13X - 24 = 80

13 X = 24 + 80

13X = 104

Divide both sides by 13

x = 104/13

x = 8

4 0
1 year ago
12 subtracted from a is greater than or equal to 17 as a mathematical equation
stira [4]

Answer:

a-12\geq 17

3 0
3 years ago
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