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2 years ago

Claire has two $20 bills, two $5 bills, and three

Mathematics

2 answers:

jarptica [38.1K]2 years ago

6 0

Answer:

153

Step-by-step explanation: 20 x 2 + 5 x 2 + 3 x 1+ 100

sladkih [1.3K]2 years ago

3 0

Answer: $153

Explanation:

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Manny receives 6 dollars each week for allowance. He also had 45 dollars saved from birthday gifts. If he currently has 111 doll

Mashutka [201]

Answer:

I'm pretty sure its D

Step-by-step explanation:

w is represented by week of saving he gets 6 dollars every week so 6w

he gets 45 dollars from his presents so he adds the 45 to the equation leaving him 111 dollars

so the equation is 6w+45=111

8 0

2 years ago

Read 2 more answers

Emily needs enough Fabric for 3 1/2 hats. Since she has half a hat done. If each bag requires 1 2/7 ft of Fabric, how much fabri

kow [346]

first off let's convert the mixed fractions to improper fractions.

$\stackrel{mixed}{3\frac{1}{2}}\implies \cfrac{3\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{7}{2}} ~\hfill \stackrel{mixed}{1\frac{2}{7}}\implies \cfrac{1\cdot 7+2}{7}\implies \stackrel{improper}{\cfrac{9}{7}}$

she already did half a hat, so we can say $\cfrac{7}{2}-\cfrac{1}{2}\implies \cfrac{7-1}{2}\implies 3$

so she only needs enough fabric to make 3 more full hats, we know each one uses 9/7 ft, so

$3\cdot \cfrac{9}{7}\implies \cfrac{27}{7}\implies 3\frac{6}{7}$

5 0

1 year ago

Trevor was reading a book for a book report. Last week, he read 35 pages of the book. This week, he read 4.5 times as many pages

navik [9.2K]

9514 1404 393

Answer:

see below

Step-by-step explanation:

Multiply the numbers as though they were integers, then mark off a number of decimal places in the product equal to the total number of decimal places in the numbers being multiplied (1).

6 0

2 years ago

Which event has a probability other than 3?

tensa zangetsu [6.8K]

The probability of compound events combines at least two simple events, either the union of two simple events or the intersection of two simple events.

6 0

2 years ago

Suppose <img src="https://tex.z-dn.net/?f=m" id="TexFormula1" title="m" alt="m" align="absmiddle" class="latex-formula"> men and

ollegr [7]

Firstly, we'll fix the postions where the $n$ women will be. We have $n!$ forms to do that. So, we'll obtain a row like:

$\underbrace{\underline{~~~}}_{x_2}W_2 \underbrace{\underline{~~~}}_{x_3}W_3 \underbrace{\underline{~~~}}_{x_4}... \underbrace{\underline{~~~}}_{x_n}W_n \underbrace{\underline{~~~}}_{x_{n+1}}$

The n+1 spaces represented by the underline positions will receive the men of the row. Then,

$x_1+x_2+x_3+...+x_{n-1}+x_n+x_{n+1}=m~~~(i)$

Since there is no women sitting together, we must write that $x_2,x_3,...,x_{n-1},x_n\ge1$ . It guarantees that there is at least one man between two consecutive women. We'll do some substitutions:

$\begin{cases}x_2=x_2'+1\\x_3=x_3'+1\\...\\x_{n-1}=x_{n-1}'+1\\x_n=x_n'+1\end{cases}$

The equation (i) can be rewritten as:

$x_1+x_2+x_3+...+x_{n-1}+x_n+x_{n+1}=m\\\\
x_1+(x_2'+1)+(x_3'+1)+...+(x_{n-1}'+1)+x_n+x_{n+1}=m\\\\
x_1+x_2'+x_3'+...+x_{n-1}'+x_n+x_{n+1}=m-(n-1)\\\\
x_1+x_2'+x_3'+...+x_{n-1}'+x_n+x_{n+1}=m-n+1~~~(ii)$

We obtained a linear problem of non-negative integer solutions in (ii). The number of solutions to this type of problem are known: $\dfrac{[(n)+(m-n+1)]!}{(n)!(m-n+1)!}=\dfrac{(m+1)!}{n!(m-n+1)!}$

[I can write the proof if you want]

Now, we just have to calculate the number of forms to permute the men that are dispposed in the row: $m!$

Multiplying all results:

$n!\times\dfrac{(m+1)!}{n!(m-n+1)!}\times m!\\\\
\boxed{\boxed{\dfrac{m!(m+1)!}{(m-n+1)!}}}$

4 0

2 years ago