7 over 32 you cant simplify it
The answer to this question is A.-1/12
Answer:
The top 20% of the students will score at least 2.1 points above the mean.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
The mean of a certain test is 14 and the standard deviation is 2.5.
This means that 
The top 20% of the students will score how many points above the mean
Their score is the 100 - 20 = 80th percentile, which is X when Z has a pvalue of 0.8. So X when Z = 0.84.
Their score is:




16.1 - 14 = 2.1
The top 20% of the students will score at least 2.1 points above the mean.
If the width is 28 inches, then divide that by 4 and you get 7. You multiply that by 5 to get the length. That would be 35. Just to check, you know that the width 28 and length 35 are in ratio 4:5 if you divide by 7. The perimeter would be 2(35+28)=63*2=126. So the perimeter is 126. The area would be 35*28 which is 980. To sum up, the answers are as follows.
Length: 35 in
Perimeter: 126 in
Area: 980 inches squared.
<h2>
Answer:</h2>

and,

<h2>
Step-by-step explanation:</h2>
In the question,
Taking the elevation of pool along the y-axis, and length of the board along the x-axis.
On drawing the illustration in the co-ordinate system we get,
lₓ = 2 m
uₓ = 2.5 m/s
and,

So,
From the equations of the laws of motion we can state that,

So,
On putting the values we can say that,

Now,
The <u>equation of the motion in the horizontal</u> can be given by,

<em><u>Therefore, the equations of the motions in the horizontal and verticals are,</u></em>

and,
