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Furkat [3]
2 years ago
14

Find the both term of the arithmetic sequence –27, -24, -21, ...

Mathematics
1 answer:
Irina-Kira [14]2 years ago
3 0

Answer:

-18 is the ans you can calculate it

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How can you know if this equation is true? 13+15=28=14
nasty-shy [4]

Answer: It is True.

Step-by-step explanation:

13 + 15 = 28

3 + 5 = 8

1 + 1 = 2

Half of 28 is 14.

28 / 2 = 14

14 * 2 = 28

Hope this helps you!

6 0
3 years ago
X= <br> (-6x+125) (11x + 6)
artcher [175]

9514 1404 393

Answer:

  x = 7

Step-by-step explanation:

The base angles of an isosceles triangle are congruent, so ...

  11x +6 = -6x +125

  17x = 119 . . . . . . . . . add 6x-6 to both sides

  x = 7 . . . . . . . . divide by 17

7 0
3 years ago
Solving Equation Again... It is in the attachment!<br> ☺
maw [93]
-7p=-2-6p
7p=2+6p
p=2
Hope this helps :)

7 0
3 years ago
Read 2 more answers
1. Simplify the fraction: 14/63​
iris [78.8K]

Answer:

2/9 is the simplified fraction (14/63 = 2/9)

6 0
2 years ago
Read 2 more answers
(WILL GIVE BRAINLIEST)Find the polynomial function with real coefficients that has zeros 1, 1 , 2+ i sqrt 3
neonofarm [45]

Answer:

x^3-x^2(4+i\sqrt{3} )+x(5+i2\sqrt{3} )-(2+i\sqrt{3} )=0

Step-by-step explanation:

We have given that this polynomial has the given zeroes of 1, 1, and 2+i\sqrt{3}, we can express the polynomial in a factored form where each zero has the form x-a (where a is our zero):

polynomial= (x-1) (x-1) (2+i\sqrt{3})

                  =(x^2+1-2x) (2+i\sqrt{3})

                   =x^3-x^2(4+i\sqrt{3} )+x(5+i2\sqrt{3} )-(2+i\sqrt{3} )=0

8 0
4 years ago
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