Answer: 3y - x - 42 = 0
Step-by-step explanation:
The equation y + 1 = -3(x - 5)
Now expand the expression by opening the brackets
y + 1 = -3x + 15
Recall,
Equation of line , y = mx + c , where m = slope
rearranging the equation above in order to determine the ( m)
y = -3x -1 + 15
y = -3x + 14
Recall again condition for perpendicularity
m₁m₂ = -1
From the equation given, m₁ = -3, therefore , to get m₂
-3 x m₂ = -1
-3m₂ = -1
Therefore m₂ = -1/-3
m₂ = 1/3
Now , to find the equation of the second line parallel to the first one,
Just replaced the -3 in the equation above by m₂ = 1/3 in
y = -3x + 14
y = x/3 + 14
Now , multiply both the RHS and LHS of the equation by 3, to make it a linear.
3y = x + 3 x 14
3y = x + 42
3y - x - 42 =0
<span>If a = b + c and c > 0, then a > b</span>
Answer: (a+3)(a+1)(a−1)
Hope this helps :)
Step-by-step explanation:
Answer:
the answer would be the second one
Step-by-step explanation:
hoped that helped
