If the Vertical angle of an isosceles triangle is equal to the sum of the base angle find the size of each angle
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Cos (B) = (a^2 + c^2 -b^2) / (2 * a * c)
cos (B) = (11^2 +17^2 -12^2) / (2 * 11 * 17)
cos (B) = (121 + 289 -144) / (374)
cos (B) = 266 / 374
cos (B) = <span> <span> <span> 0.7112299465
Angle B = </span></span></span>44.665 degrees
cos (B) = (11^2 +17^2 -12^2) / (2 * 11 * 17)
cos (B) = (121 + 289 -144) / (374)
cos (B) = 266 / 374
cos (B) = <span> <span> <span> 0.7112299465
Angle B = </span></span></span>44.665 degrees