Answer:
its=> 3×4=-3-6(use a caculator now)
Hello!
Since Staci has 7 more cats than Taylor and Taylor has x cats the expression is
let y = amount of cats Staci has
let x = amount of cats Taylor has
7 + x = y
Hope this helps!
Pick any 2 data points from the list, say (6,13) and (5,11)
compute m, slope using the slope fornula m= y2-y1/x2-x1 = 13-11/6-5=2/1=2. pick any point and write your equation in slope intercept form
y-11=2(x-5)
y-11=2x-10
y=2x+1. answer B
Function defines relationship between variables. The value of the f[g(x)] when the value of f(x)=6x+11 and g(x)=x²+6 is f[g(x)]= 36x²+47.
<h3>What is a function?</h3>
A function assigns the value of each element of one set to the other specific element of another set.
Given to us
f(x) = 6x + 11
g(x) = x² + 6
As we know the two functions, given to us f(x) = 6x + 11, therefore substitute the value of x as g(x) in order to find the value of f[g(x)] ,
![f(x) = 6x + 11\\\\f[g(x)] = 6(x^2 + 6) + 11\\\\f[g(x)] = 6x^2 + 36 + 11\\\\f[g(x)] = 6x^2 + 47](https://tex.z-dn.net/?f=f%28x%29%20%3D%206x%20%2B%2011%5C%5C%5C%5Cf%5Bg%28x%29%5D%20%3D%206%28x%5E2%20%2B%206%29%20%2B%2011%5C%5C%5C%5Cf%5Bg%28x%29%5D%20%3D%206x%5E2%20%2B%2036%20%2B%2011%5C%5C%5C%5Cf%5Bg%28x%29%5D%20%3D%206x%5E2%20%2B%2047)
Hence, the value of the f[g(x)] when the value of f(x)=6x+11 and
g(x)=x²+6 is f[g(x)]= 36x²+47.
Learn more about Function:
brainly.com/question/5245372
Answer:
(x+5)(x-3) / (x+5)(x+1)
Step-by-step explanation:
A removeable discontinuity is always found in the denominator of a rational function and is one that can be reduced away with an identical term in the numerator. It is still, however, a problem because it causes the denominator to equal 0 if filled in with the necessary value of x. In my function above, the terms (x + 5) in the numerator and denominator can cancel each other out, leaving a hole in your graph at -5 since x doesn't exist at -5, but the x + 1 doesn't have anything to cancel out with, so this will present as a vertical asymptote in your graph at x = -1, a nonremoveable discontinuity.
