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serg [7]
2 years ago
5

Which values of c will cause the quadratic equation –x2 3x c = 0 to have no real number solutions? check all that apply.

Mathematics
1 answer:
nika2105 [10]2 years ago
5 0

The given quadratic equation will not have any real solution for c<-9/4.

The given quadratic equation is:

-x^{2} +3x+c=0

<h3>What is a quadratic equation?</h3>

Any equation of the form ax^{2} +bx+c=0 is called a quadratic equation with a≠0.

In order to have no real solution, the discriminant of a quadratic equation will be less than zero.

D < 0

3^{2} -4(-1)(c) < 0

9+4c < 0

c < -\frac{9}{4}

For c < -\frac{9}{4} the given quadratic equation will have no real solutions.

Hence, the given quadratic equation will not have any real solution for c<-9/4.

To get more about quadratic equations visit:

brainly.com/question/1214333

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Which expression is equivalent to...
torisob [31]

Answer:

x^{\frac{2}{7} } y^{-\frac{3}{5} } \\  i.e answer A.

Step-by-step explanation:

This question involves knowing the following power/exponent rule:

\sqrt[n]{x^m} = x^\frac{m}{n} \\\\so \sqrt[7]{x^2} = x^\frac{2}{7} \\\\and  \\\\ \sqrt[5]{y^3} = y^\frac{3}{5} \\

Next, when a power is on the bottom of a fraction, if we want to move it to the top, this makes the power become negative.

so the y-term, when moved to the top of the fraction, becomes:

y^{-\frac{3}{5} } \\

So the answer is: x^{\frac{2}{7} } y^{-\frac{3}{5} } \\

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Answer: Yes it is.

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According to the Hypotenuse-Leg Theorem, two right triangles that have a congruent hypotenuse and a corresponding, congruent leg are congruent triangles. AC and DC are hypotenuses and they are congruent. And BC, the shared side, is a corresponding congruent leg. And since they are both right triangles, we then know that the HL Theorem applies.

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