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serg [7]
2 years ago
5

Which values of c will cause the quadratic equation –x2 3x c = 0 to have no real number solutions? check all that apply.

Mathematics
1 answer:
nika2105 [10]2 years ago
5 0

The given quadratic equation will not have any real solution for c<-9/4.

The given quadratic equation is:

-x^{2} +3x+c=0

<h3>What is a quadratic equation?</h3>

Any equation of the form ax^{2} +bx+c=0 is called a quadratic equation with a≠0.

In order to have no real solution, the discriminant of a quadratic equation will be less than zero.

D < 0

3^{2} -4(-1)(c) < 0

9+4c < 0

c < -\frac{9}{4}

For c < -\frac{9}{4} the given quadratic equation will have no real solutions.

Hence, the given quadratic equation will not have any real solution for c<-9/4.

To get more about quadratic equations visit:

brainly.com/question/1214333

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The hypotenuse of a 45°-45°-90° triangle measures 128 cm. A right triangle is shown. The length of the hypotenuse is 128 centime
Aleks [24]

Answer:

64√2 or 64 StartRoot 2 EndRoot

Step-by-step explanation:

A 45-45-90 traingle is a special traingle.  Let's say one of the leg of the triangle is x. The other one is also x because of the isosocles triangle theorem.  Therefore, using the pytagorean theorem, you find that x^2+x^2=c^2.  2(x)^2=c^2.  You then square root both sides and get c= x√2.  

Therefore, the two legs are x and the hypotenuse is x√2.  x√2=128 because the question says that the hypotenuse is 128.  Solve for x by dividing both sides by √2.  X=128/√2.  You rationalize it by multiplying the numberator and denominator of the fraction by √2.  √2*√2= 2.

X=(128√2)/2= 64√2 cm.

Since X is the leg, the answer would be 64√2

3 0
3 years ago
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LaTeX: \frac{4}{5}\times\frac{7}{10}\:=\:4 5 × 7 10 =
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Is that even an actual equation?
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Usually, in sports, we expect top athletes to get better over time. We expect future athletes to run faster, jump higher, throw
pishuonlain [190]

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125

Step-by-step explanation:

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7x - 32+9x-8+5x - 27=180 <br> what’s x?
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Answer:

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Step-by-step explanation:

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3 years ago
Find the point, M, that divides segment AB into a ratio of 2:3 if A is at (0.15) and B is at (20.0)
timama [110]

Answer:

M = (8,9)

Step-by-step explanation:

Notice that the points (0,15), and (20,0) form with the origin of coordinates (0,0),  a right angle triangle (please see attached image). This triangle has twon perpendicular sides of length 15 and 20 respectively. Therefore, we can find the length of the segment that joins points A (0,15) and B (20,0) by finding the length of the hypotenuse in a right angle triangle (with the Pythagorean Theorem):

AB=\sqrt{15^2+20^2} =\sqrt{625} =25

Now, to get a 2:3 proportion on Segment AB which is of length 25, we need to divide it in five equal parts (see the picture on the right of the attached image), and place point M at two of these divisions from point A (0,15) and along segment AB.

In order to find the appropriate location in (x,y) coordinates, we consider a smaller triangle (pictured in orange in the image) that is similar to the first larger triangle (pictured in blue). Notice that if the length of AB is 25,  each of its five equal divisions would be of length "5", and therefore two of them will render a length of "10" (which is the hypotenuse of this smaller right angle triangle.

Now, in order to find the sides of this smaller triangle (which can give us the clues on the horizontal and vertical coordinates of point M), we can use proportions.

To find the length "x" of the horizontal side , we do:

\frac{x}{10} =\frac{20}{25} \\x=\frac{10*20}{25} \\x=8

To find the length "y" of the vertical side , we do:

\frac{y}{10} =\frac{15}{25} \\y=\frac{10*15}{25} \\y=6

Then, the coordinate "x" of point M will be "8", while we can calculate the y position of point M subtracting "6" from 15 (the length of the vertical side in the original triangle). This gives us the coordinates (8,9) for point M as marked in orange in the picture.

7 0
3 years ago
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