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Gre4nikov [31]
2 years ago
11

A printer that costs x

Mathematics
1 answer:
Andre45 [30]2 years ago
4 0

Answer:

B and E are correct

Step-by-step explanation:ons

A and B have the same equation, but B has the correct description of what the equation is doing.

equation E is equivalent to equation B in that the 1.08 has been distributed to the terms within the parentheses.

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Solution for 8.5+4(1-2.5k)= -25.5
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The solution is k=19/5
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4 years ago
How do I solve this?
jok3333 [9.3K]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
The sum of two consecutive integers is one less than three times the smaller integer. Find the two integers.
Minchanka [31]

The small number is 2.

The large number is 3.

<u>Step-by-step explanation:</u>

Let the two consecutive numbers be x and x+1.

  • x be the small integer.
  • x+1 be the large integer.

The sum of these two consecutive integers = small integer + large integer

The sum of these two consecutive integers is x+x+1 = (2x+1)

It is given that,

  • The sum of two consecutive integers is one less than three times the smaller integer.
  • This means that, (2x+1) is one less than three times the smaller integer.
  • Here, the small integer is represented as x.

<u>Therefore, it can determined that :</u>

(2x+1) = 3x-1

Keeping x term on one side and constants on other side,

3x-2x = 1+1

x = 2

Therefore, the small number is 2 and the large number is x+1 = 3.

3 0
3 years ago
The number of three-digit numbers with distinct digits that can be formed using the digits 1, 2, 3, 5, 8, and 9 is ________. (Op
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There are six digits to choose from, but you're only taking three at a time, so the number of such numbers is

{}_6P_3=\dfrac{6!}{3!}=6\times5\times4=120

The first and last digits can only be even if the number takes the one of the forms "2 _ 8" or "8 _ 2". The middle number can be any of the remaining four, so there is a total of eight such numbers.

This means the probability of getting a number beginning and ending with an even digits is \dfrac8{120}=\dfrac1{15}.
7 0
3 years ago
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