Answer:
The solution to above problem is 1- $45n 2- $(250+28n) 3- $(500+20n)
Step-by-step explanation:
Answer:
G=18
Step-by-step explanation:
George-G
1/3G+G=24
4/3G=24
3/4*4/3G=24*3/4
G=18
George will be 18 years old there we can find his brothers age by dividing it by three thus 18/3=6
On a standard die the probability would be 2/6
F(x) = (-3)2 - 5(-3) + q
= -6 + 15 + q
= 9 + q
Answer:
Step-by-step explanation:
Given that A be the event that a randomly selected voter has a favorable view of a certain party’s senatorial candidate, and let B be the corresponding event for that party’s gubernatorial candidate.
Suppose that
P(A′) = .44, P(B′) = .57, and P(A ⋃ B) = .68
From the above we can find out
P(A) = ![1-0.44 = 0.56](https://tex.z-dn.net/?f=1-0.44%20%3D%200.56)
P(B) = ![1-0.57 = 0.43](https://tex.z-dn.net/?f=1-0.57%20%3D%200.43)
P(AUB) = 0.68 =
![0.56+0.43-P(A\bigcap B)\\P(A\bigcap B)=0.30](https://tex.z-dn.net/?f=0.56%2B0.43-P%28A%5Cbigcap%20B%29%5C%5CP%28A%5Cbigcap%20B%29%3D0.30)
a) the probability that a randomly selected voter has a favorable view of both candidates=P(AB) = 0.30
b) the probability that a randomly selected voter has a favorable view of exactly one of these candidates
= P(A)-P(AB)+P(B)-P(AB)
![=0.99-0.30-0.30\\=0.39](https://tex.z-dn.net/?f=%3D0.99-0.30-0.30%5C%5C%3D0.39)
c) the probability that a randomly selected voter has an unfavorable view of at least one of these candidates
=P(A'UB') = P(AB)'
=![1-0.30\\=0.70](https://tex.z-dn.net/?f=1-0.30%5C%5C%3D0.70)