Number 5 is $25. Sorry, I couldn't do the rest.
(a)
the list would be
-20, -12, -8, -1, 1, 5, 10
the other intergers would have to be greater than 1 in order to be on the correct side and cause 1 to be in the middle. They could be anything but 5 and 10 because these were already chosen.
(b)
the list would be like before
-3 was not included so one of the chosen would be -3 and the other would have to be less than -3 but not -8, -12, or -20 beacuse those were already chosen
Given:
The two ways table.
To find:
The number of girls in year 9.
Solution:
Using the two ways table, we get
Boys in year 10 = Total student in year 10 - Girls in year 10
= 256 - 123
= 133
Boys in year 9 = Total boys - Boys in year 10 - Boys in year 11
= 407 - 133 - 125
= 149
Girls in year 9 = Total students in year 9 - Boys in year 9
= 303 - 149
= 154
Therefore, the number of girls in year 9 is 154 and the correct option is C.
Answer:
MAD is 5.12
Step-by-step explanation:
The following data were obtained from the question:
42, 50, 54, 38, 48
Next, we shall determine the mean of the data. This can be obtained as follow:
Mean = summation X / n
n is the number of the data.
Summation X = 42 + 50 + 54 + 38 + 48
Summation X = 232
n = 5
Mean = summation X / n
Mean = 232 / 5
Mean = 46.4
Therefore, the mean of the data is 46.4
Finally, we shall determine the mean absolute deviation (MAD) of the data as follow:
MAD = summation |mean – X| /n
MAD = (|(46.4 – 42) + (46.4 – 50) + (46.4 – 54) + (46.4 – 38) + (46.4 – 48|) /5
MAD = |4.4 + 3.6 + 7.6 + 8.4 + 1.6| /5
MAD = 25.6/5
MAD = 5.12
Therefore, the mean absolute deviation (MAD) is 5.12
