Answer:
Step-by-step explanation:
Well, the center origin of the circle is given (h,k) = (-3,5).
Point on the circle is (x,y) = (1,8)
We have to find our radius as they gave us a point. from origin to the edge of the circle.
Using the formula: (x - h)^2 + (y - k)^2 = r^2
Plug in our (h,k) = (-3,5) and (x,y) = (1,8) to solve for radius.
(x - h)^2 + (y - k)^2 = r^2
(1 - (-3))^2 + (8 - (5))^2 = r^2
(4)^2 + (3)^2 = r^2
16 + 9 = r^2
r^2 = 25
r = 5
Answer:
Ix = Iy =
Radius of gyration x = y =
Step-by-step explanation:
Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.
Mass of disk = ρπR2
Moment of inertia about its perpendicular axis is . Moment of inertia of quarter disk about its perpendicular is
.
Now using perpendicular axis theorem, Ix = Iy = =
.
For Radius of gyration K, equate MK2 = MR2/16, K= R/4.