Answer:
V2=-20.0155m/s
Step-by-step explanation:
To answer this question we will use the principle of conservation of momentum which is
MtVt=M1V1+M2V2
1) let's find the initial velocity.
We will use,
v=a*t
v=10m/s2*2s = 20 m/s
d=vot+1/2*a*t2
d=0+1/2*10*4
d=20m
2) For the speed of the lighter piece we use,
v22=v12+2ad
0=v12+2*-9.81*(530-20)
v12=10006.2
v1=100.031m/s
3) Computing this in our conservation of momentum equation it will be-
MtVt=M1V1+M2V2
1500kg*20m/s=(1500*1/3)kg*100.031m/s + (1500*2/3)+V2
30000=50015.5+1000V2
Therefore V2=-20.0155m/s.
5. the first equation gives you the value of y. So plug in the value of y into the second equation:
3x+2(-x-7)=3.
Simplify: 3x-2x-14=3.
Subtract: 1x-14=3.
Add 14 to both sides: x=17.
Now you know the x value.
You plug in the x value into the first equation: y=-17-7
Solve: y=-24
Answer: 17, -24
Rearrange the equation:

Isolate the log on its own

To get rid of the log you must do 10^2.42

Then multiply both sides by (1.5 - x)


Solve normally

Hope that helps. Please send me a message if there's patchy bits. Also I'm sure you'll figure this out, but just in case, anywhere I've put down a 2dp shows that I've rounded the number to 2 decimal places. It becomes a pain to deal with otherwise.
Yes! It is equivalent because you are pretty much multiplying 12/20 by 10 which equals 22/30.