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3 years ago

Only number 4 part A and B pls help now

Mathematics

1 answer:

VARVARA [1.3K]3 years ago

4 0

The group of seventh graders will have 5 groups of five: 5 is the greatest multiple of 25, or 5*5=25. Then for the sixth graders there will be 4 groups of 5: because 4&5 are the greatest factors of 20 and you want the most amount of kids per group, you would have 5 kids in each group. Hope this helps.

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If SU and VX are parallel lines and mUTW = 131°, what is mVWT?

TiliK225 [7]

Answer:

∠VWT = 131°

Explanation:

∠VWT is equal to ∠UTW because they are Alternate inner angles. Since they are equal, we know that the measure of ∠VWT is 131°.

Hoped this helped!

4 0

2 years ago

Perform the following division:

timofeeve [1]

(33/4) / (2/8)
when dividing with fractions, flip what u r dividing by, then multiply
33/4 * 8/2 = 66/2 = 33...hmm...not an answer choice

let me try something..
(3 3/4) / (2/8) =
15/4 * 8/2 =
30/2 =
15 <====possibly this one if ur problem is : (3 3/4) / (2/8)

5 0

2 years ago

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The area of a rectangle is 40 meters. One of the sides is 10 meters. What are the measurements, in meters, of the

masya89 [10]

Answer:

Step-by-step explanation:

3 0

2 years ago

PLEASE HELP!

andreyandreev [35.5K]

Answer:

2,4,1

Step-by-step explanation:

3 0

2 years ago

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The constraints of a problem are listed below. What are the vertices of the feasible region?

Mamont248 [21]

Answer:

Option 4 : $(0.\frac{3}{2} ) \ , \ (0,2) \ , \ (6,0) \ , \ (\frac{9}{4} ,0)$

Step-by-step explanation:

See the attached figure:

To find the vertices of the feasible region, we need to graph the constraints, then find the area included by them, then calculate the vertices which is the intersection between each two of them.

As shown, the shaded area represents the solution of the constraints

So, the vertices of the feasible region are:

$(0.\frac{3}{2} ) \ , \ (0,2) \ , \ (6,0) \ , \ (\frac{9}{4} ,0)$

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2 years ago

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