The perimeter = sum of all sides
= 120 + 80 + 50
= 250
So 250 - 3
247
Left space for gate
Now cost of fencing = Rs 20/per meter
= 247 × 20
= Rs 4,940
Now the area of the triangular park can be found using heron's formula
S = (a+b+c)/2
S = (120+80+50)/2
S = 250/2
S = 125
Now
Herons formula = √s(s-a)(s-b)(s-c)
√125(125-120)(125-80)(120-50)
√125(5)(45)(70)
√5×5×5×5×5×3×3×5×14
After Making pairs
5×5×5×3√14
375√14
Therefore 375√14m is the area of the triangular park
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18*3 = 54
20*3 = 60
so the scale drawing would be 54cm x 60cm
Answer:
c=8
Step-by-step explanation:
Simplifying
3c + -15 = 17 + -1c
Reorder the terms:
-15 + 3c = 17 + -1c
Solving
-15 + 3c = 17 + -1c
Solving for variable 'c'.
Move all terms containing c to the left, all other terms to the right.
Add 'c' to each side of the equation.
-15 + 3c + c = 17 + -1c + c
Combine like terms: 3c + c = 4c
-15 + 4c = 17 + -1c + c
Combine like terms: -1c + c = 0
-15 + 4c = 17 + 0
-15 + 4c = 17
Add '15' to each side of the equation.
-15 + 15 + 4c = 17 + 15
Combine like terms: -15 + 15 = 0
0 + 4c = 17 + 15
4c = 17 + 15
Combine like terms: 17 + 15 = 32
4c = 32
Divide each side by '4'.
c = 8
Simplifying
c = 8
Answer:
27
Step-by-step explanation
14 is the radius so multiply by pi to get 87.96
then turn 200 fee into in which is 2400in
and divide 2400 by 87.96
