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3 years ago

Solve for x and y y+2x=2 y=-4x+10

Mathematics

1 answer:

Katena32 [7]3 years ago

7 0

Answer:

x=4 and y=(-6)

Step-by-step explanation:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

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Will give 25 points and brainliest answer if correct

Norma-Jean [14]

Let $d$ be the common difference between terms in the sequence $\{a_n\}_{n\ge1}$ . Then

$a_{19}=-58$
$a_{20}=a_{19}+d$
$a_{21}=a_{19}+2d$
$\implies-164=-58+2d\implies d=-53$

The first term in the sequence, $a_1$ , satisfies

$a_2=a_1+d$
$a_3=a_1+2d$
$a_4=a_1+3d$
...
$a_{19}=a_1+18d$
$\implies-58=a_1+18(-53)\implies a_1=896$

So the explicit formula for the $n$ -th term in the sequence is

$a_n=a_1+(n-1)d\implies a_n=896-53(n-1)$

5 0

3 years ago

In ΔABC , angle C is a right angle.

guajiro [1.7K]

Answer: Choice A. sin(A) = cos(B)

============================================================

Explanation:

The rule is that sin(A) = cos(B) if and only if A+B = 90.

Note how

sin(A) = opposite/hypotenuse = BC/AB
cos(B) = adjacent/hypotenuse = BC/AB

Since both result in the same fraction BC/AB, this helps us see why sin(A) = cos(B). Similarly, we can find that cos(A) = sin(B).

In the diagram below, the angles A and B are complementary, meaning they add to 90 degrees. So this trick only applies to right triangles.

The side lengths can be anything you want, as long as you're dealing with a right triangle.

3 0

3 years ago

In the data set below, what is the interquartile range? 7 1 5 5 9 Submit

Marizza181 [45]

Answer:

Step-by-step explanation:

The interquartile range is the difference between the upper quartile and the lower quartile.

First find the median.

The median is the middle value of the data set arranged in ascending order

1 5 5 7 9 ← data in ascending order

↑ median

The lower quartile is the middle value of the data to the left of the median. If there is not an exact middle then it the average of the values on either side of the middle.

1 5

↑ lower quartile = $\frac{1+5}{2}$ = 3

The upper quartile is the middle value of the data to the right of the median.

7 9

↑ upper quartile = $\frac{7+9}{2}$ = 8

Thus

interquartile range = 8 - 3 = 5

3 0

3 years ago

Simplify the following expression: (x^3 y^4 z^2) (y^4 z^6 x^4)

podryga [215]

Answer:

x^7y^8z^7 may be it is answer cause i think yhiai is basic of indices. U just have to add with it's common variable's powrt.

8 0

3 years ago

If you can do this please answer it.

denis23 [38]

Your answer would be rounded about 140 because first rectangle =108divided by 9 = 12 which was the the perimeter of the rectangle plus the 90 degree right triangle which was about 36 so there.

7 0

3 years ago