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2 years ago

Nick is a distance runner. He ran a mile race in Seattle Washington in a time of 4 minutes and

Mathematics

1 answer:

MAXImum [283]2 years ago

3 0

Answer:

good movie and good 8th street is the perfect way to go with your new year's day reaction and today's fun and fun hanged in

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Problem Set

insens350 [35]

5 liters (L) of 30% bleach solution contains 0.3×(5 L) = 1.5 L of bleach.

3 L of 50% bleach contains 0.5×(3 L) = 1.5 L of bleach, too.

Combined, you would have 8 L of solution containing 1.5 L + 1.5 L = 3 L of bleach, so the concentration of bleach is

(3 L) / (8 L) = 0.375 = 37.5%

7 0

3 years ago

Will give brainliest if right, please help me with my homework

Rus_ich [418]

Answer:

Step-by-step explanation:

6 0

3 years ago

What is equal to -5/4

sleet_krkn [62]

− 10/8

− 15/12

− 20/16

− 25/20

− 40/32

These are all equal, the list could go on but here are many

8 0

3 years ago

An automobile manufacturer would like to know what proportion of its customers are not satisfied by the service provided by the

zheka24 [161]

Answer:

The sample size needed if the margin of error of the confidence interval is to be about 0.04 is 18.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

Past studies suggest this proportion will be about 0.15

This means that $p = 0.15$

Find the sample size needed if the margin of error of the confidence interval is to be about 0.04

This is n when M = 0.04. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 1.96\sqrt{\frac{0.15*0.85}{n}}$

$0.04\sqrt{n} = 1.96\sqrt{0.15*0.85}$

$\sqrt{n} = \frac{1.96\sqrt{0.15*0.85}}{0.04}$

$(\sqrt{n})^{2} = (\frac{1.96\sqrt{0.15*0.85}}{0.04})^{2}$

$n = 17.5$

Rounding up

The sample size needed if the margin of error of the confidence interval is to be about 0.04 is 18.

8 0

3 years ago

A woman is looking for a bigger square office. She finds an office twice the area of her current office. If the perimeter of her

Sauron [17]

88×2=176this is the answer

4 0

3 years ago

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