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chubhunter [2.5K]
2 years ago
14

For a soccer practice, the coach set up four cones, labeled W, X, Y, and Z, to mark the edges of the rectangular field.Suppose t

he field is drawn on a coordinate plane, where the x- and y-values represent the position, in yards, from the center of the field, which is located at (0, 0). The location of the cones are as follows.Cone W is located at (-38, -53).Cone X is located at (-38, 53).Cone Y is located at (38, 53).Cone Z is located at (38, -53).What is the perimeter of the field?
Mathematics
1 answer:
Ratling [72]2 years ago
3 0

The perimeter of the field is 364 yards.

The distance between two points A(x_1, y_1) and B(x_2, y_2) is AB=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}.

WX=\sqrt{(-38-(-38))^2+(53-(-53))^2}=106 units

XY=\sqrt{(38-(-38))^2+(53-(53))^2}=76 units

Perimeter = 2 (l+w), where l is length and w is width.

Perimeter = 2(106+76)

=364 yards

Learn more about perimeter of rectangle here:

brainly.com/question/2142493?referrer=searchResults

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