Total Number of cards = 4 + 6 = 10
Number of Football cards = 4
Number of Basketball cards = 6
Probability of choosing a football card = 4/10 = 0.4
Since this card is replaced, the total number of cards will remain the same.
Probability of selecting a basketball card = 6/10 = 0.6
Since, the two events are independent, the probability of selecting a football and a basketball card will be the product of two probabilities we calculated.
Thus, probability of selecting a football card and then a basketball card = 0.4 x 0.6 = 0.24
Answer:
The answer is B.
Step-by-step explanation:
Hope it helps!!
4t<span>²
= 4(3)</span><span>²
= 4 x 9
= 36</span>
9(3b-2) Iv factorised it but I dont know the rest sorry
