After 2 years, a certain car is worth $16600. When it is 9 years old, the same car is then worth
1 answer:
The linear function that describes the situation is:
y = -950x + 18500.
- The slope of -950 means that the price of the car decays $950 per year.
- The y-intercept of 18500 means that the initial value of the car is of $18,500.
- The x-intercept of 19.47 means that the value of car is of $0 after 19.47 years.
A linear function is modeled by:
In which:
- m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.
- b is the y-intercept, which is the value of y when x = 0.
In this problem, in 7 years, the price of the car decays by $6,650, hence the slope is given by:
m = -6650/7 = -950.
The slope of -950 means that the price of the car decays $950 per year.
Then, the equation is:
y = -950x + b.
After 2 years, a certain car is worth $16600, hence when x = 2, y = 16600, and:
16600 = -950(2) + b
b = 18500.
The equation is:
y = -950x + 18500.
The y-intercept of 18500 means that the initial value of the car is of $18,500.
The x-intercept is found when y = 0, hence:
-950x + 18500 = 0.
x = 18500/950
x = 19.47.
The x-intercept of 19.47 means that the value of car is of $0 after 19.47 years.
More can be learned about linear functions at brainly.com/question/24808124
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Solution -
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The probability of getting any other number rather than 6 would be
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So
E(X) = Expectation value = ( ∵ $5 gain so +ve and $2 loss so -ve)
=
∴ So Merrill will lose dollar