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kogti [31]
3 years ago
6

What is 0.787878....... as a fraction

Mathematics
1 answer:
Vlad1618 [11]3 years ago
3 0

Answer:

26/33

Step-by-step explanation:

The process is:

0.787878

78.7878

78/99x then simplify

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4 years ago
The average lifetime of a certain new cell phone is 3.4 years. The manufacturer will replace any cell phone failing within three
melisa1 [442]

Answer:

68% of these phones last 3.87 years.

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

f(x) = \mu e^{-\mu x}

In which \mu = \frac{1}{m} is the decay parameter.

The probability that x is lower or equal to a is given by:

P(X \leq x) = \int\limits^a_0 {f(x)} \, dx

Which has the following solution:

P(X \leq x) = 1 - e^{-\mu x}

The probability of finding a value higher than x is:

P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}

The average lifetime of a certain new cell phone is 3.4 years.

This means that m = 3.4, \mu = \frac{1}{3.4} = 0.2941

So

P(X \leq x) = 1 - e^{-0.2941x}

68% of these phones last how long (in years)?

This is x for which:

P(X \leq x) = 0.68

P(X \leq x) = 1 - e^{-0.2941x}

Then

0.68 = 1 - e^{-0.2941x}

e{-0.2941x} = 0.32

\ln{e{-0.2941x}} = \ln{0.32}

-0.2941x = \ln{0.32}

x = -\frac{\ln{0.32}}{0.2941}

x = 3.87

68% of these phones last 3.87 years.

4 0
3 years ago
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