We can use the SSS congruence theorem to prove that the two triangles in the attached figure are congruent. The SSS or side-side-side theorem states that each side in the first triangle must have the same measurement or must be congruent on each of the opposite side of another triangle. In this problem, for the first triangle, we have sides AC, CM, AM while in the second triangle we have sides BC, CM, and BM. By SSS congruent theorem, we have the congruent side as below:
AC = BC
CM = CM
AM = BM
The answer is SSS theorem.
Hello from MrBillDoesMath!
Answer:
Top line: y = (2/3)x + 2
Bottom line: y = (2/3)x -1
Discussion:
The graph provided is hard to read but I did the best I could.
The top line appears to pass through the points (0,2) and (-3,0)
For this line
m = change y /change x = (0-2)/(-3-0) = -2/-3 = +2/3. So
y = mx + b => y = (2/3) x+ b. As the line passes through (0,2) set x = 0, y= 2 in y = (2/3)x + b =>
2 = (2/3) 0 + b => b = 2
Therefore y = (2/3)x + 2
The bottom line appears to pass through the points (0,-1) and (3,1)
For this line
m = change y /change x = (1-(-1)) /(3-0) = +2/-3. So
y = mx + b => y = (2/3) x+ b. As the line passes through (0,-1) set x = 0, y= -1 in y = (2/3)x + b =>
-1 = (2/3) 0 + b => b = -1
Therefore y = (2/3)x + -1
Thank you,
MrB
<h3>
Answer: addition property of inequality</h3>
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Explanation:
These are the steps to focus on
step 3: -6x - 8 < -2
step 4: -6x < 6
The move from the third step to the fourth step has us adding 8 to both sides. Therefore, we use the addition property of inequality.
That property has four forms
- If
then 
- If
then 
- If
then 
- If
then 
It's similar to the idea of starting with a = b, then adding c to both sides to get a+c = b+c
We add the same thing to both sides to keep things balanced.
The answer is 8/10 and that simplified is 4/5
