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kiruha [24]
3 years ago
6

Help please I’ll give brainliest

Mathematics
2 answers:
3241004551 [841]3 years ago
7 0

Answer:

A

Step-by-step explanation:

jenyasd209 [6]3 years ago
6 0

Answer:

"ALL of the beverages at The Zest Nest ARE LIKELY to contain 46 grams of sugar or less, but NONE of the beverages at Jim's Juice Join ARE LIKELY to contain LESS THAN 46 grams of sugar."

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Factorise fully : <br><br>4(x - y)^2 - 9(x + y)^2​
sergeinik [125]

Answer:

- ( 5x + y ) ( x + 5y )

or

-5x^2 - 5y^2 - 26xy

8 0
3 years ago
Read 2 more answers
Simplify 6 - (-2) - 3(-5).<br> -11<br> -7<br> 19<br> 23
Sergeeva-Olga [200]
6 - (-2) - 3(-5) = (6 + 2) + 15 = 8 + 15 = 23

Your answer is D. the last one :)
4 0
3 years ago
Read 2 more answers
The first term of an arithmetic sequence is -5, and the tenth term is 13. Find the common difference.
dlinn [17]

\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ d=\textit{common difference}\\[-0.5em] \hrulefill\\ a_1=-5\\ n=10\\ a_{10}=13 \end{cases} \\\\\\ a_{10}=a_1+(10-1)d\implies 13=-5+(10-1)d \\\\\\ 13=-5+9d\implies 18=9d\implies \cfrac{18}{9}=d\implies \boxed{2=d}

7 0
3 years ago
Find an ordered pair , x y that is a solution to the equation.x-3y=6
a_sh-v [17]
Hi there!

Let x=1

X-3y=6
1-3y=6
-3y=6-1
-3y=5
Y=-5/3

Therefore a point would be (1, -5/3)

Hope this helps!
6 0
3 years ago
How many solutions are there to the equation x1 + x2 + x3 + x4 + x5 + x6 = 25 in which each xi is a non-negative integer and … (
prohojiy [21]

Answer:

The equation x1 + x2 + x3 + x4 + x5 + x6 = 25 in which each xi is a non-negative integer and … Will have:

(a) 6 solutions where there are no other restrictions.

(b) 4 Solutions for xi ≥ 3 for i = 1, 2, 3, 4, 5, 6(x3 + x4 +x5 + x6 = 25)

(c) 4 Solutions for 3 ≤ x1 ≤ 10

( x3 + x4 + x5 + x6 = 25)

(d) 5 Solutions for 2 ≤ x2 ≤ 7

Step-by-step explanation:

The equation have 6 unknown variables . This means it will have 6 solutions when no condition is imposed as in (a) above. The number of unknown variables in the equation will give the numbers of solutions

When the conditions are imposed, the numbers of unknown variables will give the number of solutions.

In (b) and (c), the equation will reduce to x3 + x4 +x5 + x6 = 25) and the unknown variables are 4, giving 4 solutions

In (d), the equation will reduce be 5 unknown variables(x2 + x3 + x4 +x5 + x6 = 25) and the solution is 5

8 0
3 years ago
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