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2 years ago

PLS HELP!

Mathematics

1 answer:

polet [3.4K]2 years ago

8 0

Answer:

B.) y=csc x

Step-by-step explanation:

The cosecant function has a minimum magnitude of 1, so its range excludes any values in the range -1 < y < 1.

y = csc(x) . . . has a range that does not include -0.8

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liberstina [14]

Answer:

Inverse of f exists.

Step-by-step explanation:

From the graph attached,

If we do the horizontal line test for the function graphed,

We find the function as one to one function.

In other words for every input value (x-value) there is a different output value.

Since, for one-to-one functions, inverse of the functions exist.

Therefore, the answer will be,

The inverse of 'f' exists.

7 0

3 years ago

18 + 4(3x - 7) = -70

Elan Coil [88]

If you’re trying to find the value of x it is -5

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3 years ago

Solve for x. -3.5x = -35

r-ruslan [8.4K]

Answer:

$- 3.5x = - 35 \\ x = \frac{ - 35}{ - 3.5}( - \div - = + ) = \frac{35}{35 \times .1} \\ = \frac{1}{.1} = 10 \\ x = 10 \\ thank \: you$

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3 years ago

Read 2 more answers

A catering company loses $110 as a result of delay. The 5 owners of the company must share the loss equally. Which integer repre

san4es73 [151]

What you have to do first is you have 5 owners correct? Well you take anything they're sharing in this case it's delay/debt, so you divide $110 by 5 and you should get $22. This means that each owner would have to pay $22 to the delay.

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3 years ago

Read 2 more answers

I need to know the improper fractions answers for:

zmey [24]

Answer:

Part 1) $x=\frac{15}{2}\ units$

Part 2) $z=\frac{15\sqrt{3}}{2}\ units$

Part 3) $y= \frac{15\sqrt{3}}{4}\ units$

Part 4) $b= \frac{45}{4}\ units$

Step-by-step explanation:

step 1

Find the value of x

In the large right triangle

$cos(60^o)=\frac{x}{15}$ ----> by CAH (adjacent side divided by the hypotenuse)

Remember that

$cos(60^o)=\frac{1}{2}$

substitute

$\frac{1}{2}=\frac{x}{15}$

solve for x

$x=\frac{15}{2}\ units$ ---> improper fraction

step 2

Find the value of z

In the large right triangle

Applying the Pythagorean Theorem

$15^2=x^2+z^2$

substitute the value of x

$15^2=(\frac{15}{2})^2+z^2$

solve for z

$z^2=15^2-(\frac{15}{2})^2$

$z^2=225-\frac{225}{4}$

$z^2=\frac{675}{4}$

$z=\frac{\sqrt{675}}{2}\ units$

simplify

$z=\frac{15\sqrt{3}}{2}\ units$

step 3

Find the value of y

In the right triangle of the right

$sin(30^o)=\frac{y}{z}$ ---> by SOH (opposite side divided by the hypotenuse)

substitute the given values of y and z

Remember that

$sin(30^o)=\frac{1}{2}$

$\frac{1}{2}=y:\frac{15\sqrt{3}}{2}$

solve for y

$\frac{1}{2}= \frac{2y}{15\sqrt{3}}$

$y= \frac{15\sqrt{3}}{4}\ units$

step 4

Find the value of b

In the right triangle of the right

$cos(30^o)=\frac{b}{z}$ ---> by CAH (adjacent side divided by the hypotenuse)

substitute the given values of y and z

Remember that

$cos(30^o)=\frac{\sqrt{3}}{2}$

$\frac{\sqrt{3}}{2}=b:\frac{15\sqrt{3}}{2}$

solve for y

$\frac{\sqrt{3}}{2}= \frac{2b}{15\sqrt{3}}$

$b= \frac{45}{4}\ units$

7 0

3 years ago